How far up on a wall of a building will a 10-meter ladder reach if the foot of the ladder is 1,25 metres from the wall? Draw the situation and then explain your answer.

This maximum dimension is the length of the diagonal of the doorway. We use the Pythagorean theorem, where the height and width are the legs of a right-angled triangle, and the diagonal is the hypotenuse.
Let $h = 2.5$ m (height) and $w = 1$ m (width).
The diagonal $d$ is given by:

The table's diameter is 2.7 m.
The doorway's height is 2.5 m.
The doorway's width is 1 m.
The doorway's diagonal is approximately 2.6926 m.

Since the table's diameter (2.7 m) is greater than the doorway's height (2.5 m), width (1 m), and even its diagonal (2.6926 m), the table top will not fit.

Yes/No: ❌ No
Reason: The diameter of the table top (2.7 m) is greater than the maximum possible dimension it could pass through the doorway, which is the diagonal of the doorway (approximately 2.69 m).

The Pythagorean theorem states $a^2 + b^2 = c^2$.

The ladder will reach approximately $\boxed{9.92 \text{ meters}}$ up the wall.

Length ($l$) = 12 units
Width ($w$) = 9 units
Height ($h$) = 8 units

The formula for the space diagonal of a rectangular prism is:

The length of the longest pole is $\boxed{17 \text{ units}}$.

The last question about "the measures of the interior angles of the following..." is incomplete. Please provide the full question for me to solve it.