Which of the two containers would carry more: a square box with sides of 200mm each, or a rectangular box with sides of 80mm each and a length of 800mm?

Mathematics
Which of the two containers would carry more: a square box with sides of 200mm each, or a rectangular box with sides of 80mm each and a length of 800mm?

ScanSolve AI Answer

Answer

Vsquarebox=8,000,000mm3Vrectangularbox=6,480,000mm3(squarebox>rectangularbox)V_{square box} = 8{,}000{,}000 mm^{3} V_{rectangular box} = 6{,}480{,}000 mm^{3} (square box > rectangular box)

Part (a)
To measure the volume (capacity) of the irregular-shaped glass bowl and vase:

Step 1: Fill the bowl or vase completely to the brim with water.

Step 2: Carefully pour all the water into a graduated cylinder or measuring container without spilling.

Step 3: Read and record the volume of water from the measuring scale. This equals the internal volume of the bowl or vase.

Units: Volume in cm³ or mL (1 cm³ = 1 mL), depending on the measuring cylinder.

Part (b)

Step 1: Square box (cube) with all sides 200 mm.
Formula: V1=s3V_1 = s^3, where s=200s = 200 mm.

V1=200×200×200 mm3V_1 = 200 \times 200 \times 200~mm^3

200×200=40,000200 \times 200 = 40{,}000
40,000×200=8,000,000 mm340{,}000 \times 200 = 8{,}000{,}000~mm^3

Step 2: Rectangular box with sides 90 mm, 90 mm, and length 800 mm.
Formula: V2=w×h×lV_2 = w \times h \times l, where w=90w = 90 mm, h=90h = 90 mm, l=800l = 800 mm.

V2=90×90×800 mm3V_2 = 90 \times 90 \times 800~mm^3

90×90=8,10090 \times 90 = 8{,}100
8,100×800=8,100×8×100=64,800×100=6,480,000 mm38{,}100 \times 800 = 8{,}100 \times 8 \times 100 = 64{,}800 \times 100 = 6{,}480{,}000~mm^3

Step 3: Compare volumes (convert to cm³ for clarity: divide by 1{,}000).
V1=8,000,000 mm3=8,000 cm3V_1 = 8{,}000{,}000~mm^3 = 8{,}000~cm^3
V2=6,480,000 mm3=6,480 cm3V_2 = 6{,}480{,}000~mm^3 = 6{,}480~cm^3
V1>V2V_1 > V_2.

The square box carries more volume.
V_{square box = 8{,}000{,}000 mm^{3}
V_{rectangular box} = 6{,}480{,}000 mm^{3}
(square box > rectangular box)}

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Quick Answer

Part (a) To measure the volume (capacity) of the irregular-shaped glass bowl and vase: Step 1: Fill the bowl or vase completely to the brim with water.

Which of the two containers would carry more: a square box with sides of 200mm each, or a rectangular box with sides of 80mm each and a length of 800mm?
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Part (a) To measure the volume (capacity) of the irregular-shaped glass bowl and vase: Step 1: Fill the bowl or vase completely to the brim with water. Step 2: Carefully pour all the water into a graduated cylinder or measuring container without spilling. Step 3: Read and record the volume of water from the measuring scale. This equals the internal volume of the bowl or vase. Units: Volume in cm³ or mL (1 cm³ = 1 mL), depending on the measuring cylinder. Part (b) Step 1: Square box (cube) with all sides 200 mm. Formula: V_1 = s^3, where s = 200 mm. V_1 = 200 × 200 × 200~mm^3 200 × 200 = 40,000 40,000 × 200 = 8,000,000~mm^3 Step 2: Rectangular box with sides 90 mm, 90 mm, and length 800 mm. Formula: V_2 = w × h × l, where w = 90 mm, h = 90 mm, l = 800 mm. V_2 = 90 × 90 × 800~mm^3 90 × 90 = 8,100 8,100 × 800 = 8,100 × 8 × 100 = 64,800 × 100 = 6,480,000~mm^3 Step 3: Compare volumes (convert to cm³ for clarity: divide by 1,000). V_1 = 8,000,000~mm^3 = 8,000~cm^3 V_2 = 6,480,000~mm^3 = 6,480~cm^3 V_1 > V_2. The square box carries more volume. V_square box = 8,000,000 mm^3 V_rectangular box = 6,480,000 mm^3 (square box > rectangular box)