. Find the equation of the line passing through the intersection of the lines x+y=5 and 2x−y−7=0, and parallel to x-axis

of the two lines:

• From $x + y = 5$, we can express $y$ as $y = 5 - x$.
• Substitute $y$ into the second equation: $$2x - (5 - x) - 7 = 0 \implies 2x - 5 + x - 7 = 0 \implies 3x - 12 = 0 \implies x = 4.$$
• Substitute $x = 4$ back into $y = 5 - x$: $$y = 5 - 4 = 1.$$
• The intersection point is $(4, 1)$.

• A line parallel to the x-axis has the form $y = k$, where $k$ is a constant.
• Since the line must pass through the point $(4, 1)$, the equation is: $$y = 1.$$

Thus, the equation of the line is $y = 1$.