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Calculate the matrix multiplication Ax for the given matrices.

Mathematics

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Answer

[24−9−23]\begin{bmatrix} 24 \\ -9 \\ -23 \end{bmatrix}

Step-by-step solution

4 steps
  1. Calculate the first element of the resulting matrix, c1,1c_{1,1}.

    This is obtained by multiplying the elements of the first row of the first matrix by the corresponding elements of the column vector and summing them.

    c1,1=(6)(4)+(2)(−2)+(4)(1)c_{1,1} = (6)(4) + (2)(-2) + (4)(1) c1,1=24−4+4c_{1,1} = 24 - 4 + 4 c1,1=24c_{1,1} = 24
  2. Calculate the second element of the resulting matrix, c2,1c_{2,1}.

    This is obtained by multiplying the elements of the second row of the first matrix by the corresponding elements of the column vector and summing them.

    c2,1=(−1)(4)+(4)(−2)+(3)(1)c_{2,1} = (-1)(4) + (4)(-2) + (3)(1) c2,1=−4−8+3c_{2,1} = -4 - 8 + 3 c2,1=−12+3c_{2,1} = -12 + 3 c2,1=−9c_{2,1} = -9
  3. Calculate the third element of the resulting matrix, c3,1c_{3,1}.

    This is obtained by multiplying the elements of the third row of the first matrix by the corresponding elements of the column vector and summing them.

    c3,1=(−2)(4)+(9)(−2)+(3)(1)c_{3,1} = (-2)(4) + (9)(-2) + (3)(1) c3,1=−8−18+3c_{3,1} = -8 - 18 + 3 c3,1=−26+3c_{3,1} = -26 + 3 c3,1=−23c_{3,1} = -23
  4. Assemble the resulting matrix.

    Ax=[c1,1c2,1c3,1]=[24−9−23]Ax = \begin{bmatrix} c_{1,1} \\ c_{2,1} \\ c_{3,1} \end{bmatrix} = \begin{bmatrix} 24 \\ -9 \\ -23 \end{bmatrix}

    The final answer is [24−9−23]\begin{bmatrix} 24 \\ -9 \\ -23 \end{bmatrix}.

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