Solve the first part of the inequality: 4 − 3x < x + 12.

$4 - 3x < x + 12$.

Subtract $x$ from both sides:

Subtract 4 from both sides:

Divide by $-4$. Remember to reverse the inequality sign when dividing by a negative number:

$x + 12 \le \frac{-3x + 29}{2}$.

Multiply both sides by 2:

Add $3x$ to both sides:

Subtract 24 from both sides:

Divide by 5:

We have $x > -2$ and $x \le 1$. This can be written as:

The solution includes all numbers greater than $-2$ and less than or equal to 1. On a number line, this is represented by an open circle at $-2$ (since $-2$ is not included), a closed circle at 1 (since 1 is included), and a line segment connecting these two points.

<-----|-----|-----|-----|-----|-----|-----|----->
     -3    -2    -1     0     1     2     3
           o------------------•

The solution is $\boxed{-2 < x \le 1}$.

The evaluated expression is $\boxed{\frac{9}{4}}$.

On 12/1/2024, the tourist sells SAR to the bank, so the bank buys SAR.
Buying rate for 1 SAR = 7.08 Ksh.
Amount in Ksh = $15\,000 \text{ SAR} \times 7.08 \text{ Ksh/SAR} = 106\,200 \text{ Ksh}$.

Amount spent = 53 075 Ksh.
Remaining Ksh = $106\,200 \text{ Ksh} - 53\,075 \text{ Ksh} = 53\,125 \text{ Ksh}$.

On 12/2/2024, the tourist buys Tsh from the bank, so the bank sells Tsh.
Selling rate for 100 Tanzanian Shillings = 21.25 Ksh.
This means 1 Tsh = $\frac{21.25}{100} \text{ Ksh} = 0.2125 \text{ Ksh}$.
Amount in Tsh = $\frac{\text{Remaining Ksh}}{\text{Ksh per Tsh}}$
Amount in Tsh = $\frac{53\,125 \text{ Ksh}}{0.2125 \text{ Ksh/Tsh}} = 250\,000 \text{ Tsh}$.

The amount received in Tanzanian shillings is $\boxed{250\,000 \text{ Tsh}}$.