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Solve the following division problems: 1. 864 learners on a trip, buses hold 48 learners each, how many buses? 2. 560 apples packed into bags of 14, how many bags? 3. Use box method to solve 728 ÷ 26.

Mathematics

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Answers

3 parts
a

28\text{28}

b

52\text{52}

c

30\text{30}

Step-by-step solution

10 steps

Here are the solutions to your homework problems:

1. A bus carries 48 learners, 864 learners are going on a trip, how many buses are needed?

Step 1: To find the number of buses needed, divide the total number of learners by the capacity of one bus.

Number of buses=Total learnersLearners per bus\text{Number of buses} = \frac{\text{Total learners}}{\text{Learners per bus}} Number of buses=86448\text{Number of buses} = \frac{864}{48}

Step 2: Perform the division.

1848)864‾−48↓384−3840\begin{array}{r} 18 \\ 48 \overline{) 864} \\ -48 \downarrow \\ \hline 384 \\ -384 \\ \hline 0 \end{array}
  • Answer: 18 buses\boxed{\text{18 buses}}

2. A shop packs 560 apples into bags of 14. How many bags are filled?

Step 1: To find the number of bags filled, divide the total number of apples by the number of apples per bag.

Number of bags=Total applesApples per bag\text{Number of bags} = \frac{\text{Total apples}}{\text{Apples per bag}} Number of bags=56014\text{Number of bags} = \frac{560}{14}

Step 2: Perform the division.

4014)560‾−56↓00−00\begin{array}{r} 40 \\ 14 \overline{) 560} \\ -56 \downarrow \\ \hline 00 \\ -0 \\ \hline 0 \end{array}
  • Answer: 40 bags\boxed{\text{40 bags}}

3. Calculate the following using box method:

Part a· 4 steps

728÷26728 \div 26

  1. Set up the box method.

    We want to find how many groups of 26 are in 728.
    We can start by taking out multiples of 26 that are easy to calculate.

    ×20826520208\begin{array}{|c|c|c|} \hline \times & 20 & 8 \\ \hline 26 & 520 & 208 \\ \hline \end{array}
  2. Subtract the first partial product from the dividend.

    728−(26×20)=728−520=208728 - (26 \times 20) = 728 - 520 = 208
  3. Divide the remaining amount by the divisor.

    208÷26=8208 \div 26 = 8
  4. Add the partial quotients.

    20+8=2820 + 8 = 28
    • Answer: 28\boxed{\text{28}}

Part b

52\text{52}

936÷18936 \div 18

  1. Set up the box method.

    We want to find how many groups of 18 are in 936.

    ×5021890036\begin{array}{|c|c|c|} \hline \times & 50 & 2 \\ \hline 18 & 900 & 36 \\ \hline \end{array}
  2. Subtract the first partial product from the dividend.

    936−(18×50)=936−900=36936 - (18 \times 50) = 936 - 900 = 36
  3. Divide the remaining amount by the divisor.

    36÷18=236 \div 18 = 2
  4. Add the partial quotients.

    50+2=5250 + 2 = 52
    • Answer: 52\boxed{\text{52}}

Part c

30\text{30}

750÷25750 \div 25

  1. Set up the box method.

    We want to find how many groups of 25 are in 750.

    ×3025750\begin{array}{|c|c|} \hline \times & 30 \\ \hline 25 & 750 \\ \hline \end{array}
  2. Divide the dividend by the divisor directly.

    750÷25=30750 \div 25 = 30
    • Answer: 30\boxed{\text{30}}
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