Solve the following division problems: 255/6, 362/8, 779/7.

Divide 15 by 6. $15 \div 6 = 2 \text{ with a remainder of } 3$ The quotient is 42 with a remainder of 3. $\boxed{\text{42 R 3}}$

14. $\frac{362}{8}$

Divide 42 by 8. $42 \div 8 = 5 \text{ with a remainder of } 2$ The quotient is 45 with a remainder of 2. $\boxed{\text{45 R 2}}$

15. $\frac{779}{7}$

Divide 7 by 7. $7 \div 7 = 1$

Divide 9 by 7. $9 \div 7 = 1 \text{ with a remainder of } 2$ The quotient is 111 with a remainder of 2. $\boxed{\text{111 R 2}}$