Solve these division problems: 56 ÷ 3, 63 ÷ 4, 74 ÷ 5, 104 ÷ 8

To divide 56 by 3, we find how many groups of 3 are in 56.
We can take out $10 \times 3 = 30$.
Remaining: $56 - 30 = 26$.
Next, we find how many groups of 3 are in 26.
We know $3 \times 8 = 24$.
Remaining: $26 - 24 = 2$.
So, $56 \div 3 = 10 + 8$ with a remainder of 2.

$$56 \div 3 = \boxed{18 \text{ remainder } 2}$$

To divide 63 by 4, we find how many groups of 4 are in 63.
We can take out $10 \times 4 = 40$.
Remaining: $63 - 40 = 23$.
Next, we find how many groups of 4 are in 23.
We know $4 \times 5 = 20$.
Remaining: $23 - 20 = 3$.
So, $63 \div 4 = 10 + 5$ with a remainder of 3.

$$63 \div 4 = \boxed{15 \text{ remainder } 3}$$

To divide 74 by 5, we find how many groups of 5 are in 74.
We can take out $10 \times 5 = 50$.
Remaining: $74 - 50 = 24$.
Next, we find how many groups of 5 are in 24.
We know $5 \times 4 = 20$.
Remaining: $24 - 20 = 4$.
So, $74 \div 5 = 10 + 4$ with a remainder of 4.

$$74 \div 5 = \boxed{14 \text{ remainder } 4}$$

To divide 104 by 8, we find how many groups of 8 are in 104.
We can take out $10 \times 8 = 80$.
Remaining: $104 - 80 = 24$.
Next, we find how many groups of 8 are in 24.
We know $8 \times 3 = 24$.
Remaining: $24 - 24 = 0$.
So, $104 \div 8 = 10 + 3$ with no remainder.

$$104 \div 8 = \boxed{13}$$

To divide 107 by 8, we find how many groups of 8 are in 107.
We can take out $10 \times 8 = 80$.
Remaining: $107 - 80 = 27$.
Next, we find how many groups of 8 are in 27.
We know $8 \times 3 = 24$.
Remaining: $27 - 24 = 3$.
So, $107 \div 8 = 10 + 3$ with a remainder of 3.

$$107 \div 8 = \boxed{13 \text{ remainder } 3}$$

To divide 88 by 5, we find how many groups of 5 are in 88.
We can take out $10 \times 5 = 50$.
Remaining: $88 - 50 = 38$.
Next, we find how many groups of 5 are in 38.
We know $5 \times 7 = 35$.
Remaining: $38 - 35 = 3$.
So, $88 \div 5 = 10 + 7$ with a remainder of 3.

$$88 \div 5 = \boxed{17 \text{ remainder } 3}$$