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Solve the following division problems using long division: 1. 651 / 21 2. 645 / 15 3. 992 / 45

Mathematics

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Here are the solutions using long division.

1. 651÷21651 \div 21

  1. Divide the first part of the dividend (65) by the divisor (21).

    21 goes into 65 two times. 21×3=6321 \times 3 = 63.
    Subtract 63 from 65: 65−63=265 - 63 = 2.

  2. Bring down the next digit of the dividend (1) to form 21.

    Now divide 21 by 21.
    21 goes into 21 one time. 21×1=2121 \times 1 = 21.
    Subtract 21 from 21: 21−21=021 - 21 = 0.

    The quotient is 31 with a remainder of 0.

    3121)651‾−63↓21−210\begin{array}{r} 31 \\ 21 \overline{) 651} \\ -63 \downarrow \\ \hline 21 \\ -21 \\ \hline 0 \end{array}

    The answer is 31\boxed{31}.

    2. 645÷15645 \div 15

  3. Divide the first part of the dividend (64) by the divisor (15).

    15 goes into 64 four times. 15×4=6015 \times 4 = 60.
    Subtract 60 from 64: 64−60=464 - 60 = 4.

  4. Bring down the next digit of the dividend (5) to form 45.

    Now divide 45 by 15.
    15 goes into 45 three times. 15×3=4515 \times 3 = 45.
    Subtract 45 from 45: 45−45=045 - 45 = 0.

    The quotient is 43 with a remainder of 0.

    4315)645‾−60↓45−450\begin{array}{r} 43 \\ 15 \overline{) 645} \\ -60 \downarrow \\ \hline 45 \\ -45 \\ \hline 0 \end{array}

    The answer is 43\boxed{43}.

    3. 992÷45992 \div 45

  5. Divide the first part of the dividend (99) by the divisor (45).

    45 goes into 99 two times. 45×2=9045 \times 2 = 90.
    Subtract 90 from 99: 99−90=999 - 90 = 9.

  6. Bring down the next digit of the dividend (2) to form 92.

    Now divide 92 by 45.
    45 goes into 92 two times. 45×2=9045 \times 2 = 90.
    Subtract 90 from 92: 92−90=292 - 90 = 2.

    The quotient is 22 with a remainder of 2.

    2245)992‾−90↓92−902\begin{array}{r} 22 \\ 45 \overline{) 992} \\ -90 \downarrow \\ \hline 92 \\ -90 \\ \hline 2 \end{array}

    The answer is 22 R 2\boxed{22 \text{ R } 2} or 22245\boxed{22 \frac{2}{45}}.

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