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Solve the following equations: a) 2x3 = 16 b) 125^x = (1)/(5)

Mathematics

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Answers

2 parts
a

x=2x = 2

b

x=−13x = -\frac{1}{3}

Step-by-step solution

6 steps

Here are the solutions to the equations:

Part a· 2 steps

Solve 2x3=162x^3 = 16

  1. Divide both sides by 2.

    2x32=162\frac{2x^3}{2} = \frac{16}{2} x3=8x^3 = 8
  2. Take the cube root of both sides.

    x=83x = \sqrt[3]{8} x=2x = 2

    The solution is x=2\boxed{x = 2}.

Part b

x=−13x = -\frac{1}{3}

Solve 125x=15125^x = \frac{1}{5}

  1. Express both sides with the same base.

    Note that 125=53125 = 5^3 and 15=5−1\frac{1}{5} = 5^{-1}.

    (53)x=5−1(5^3)^x = 5^{-1}
  2. Apply the exponent rule (am)n=amn(a^m)^n = a^{mn}.

    53x=5−15^{3x} = 5^{-1}
  3. Since the bases are the same, equate the exponents.

    3x=−13x = -1
  4. Divide by 3 to solve for xx.

    x=−13x = -\frac{1}{3}

    The solution is x=−13\boxed{x = -\frac{1}{3}}.

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