Solve the following expression: (3+4-6÷2+2)+[(9÷3+6×5)÷11]×[(4+5-6)+(18-3×4)]÷9=

First, perform the division.

$$3+4-6 \div 2+2 = 3+4-3+2$$

Next, perform additions and subtractions from left to right.

$$3+4-3+2 = 7-3+2 = 4+2 = 6$$

First, simplify the innermost parentheses $(9 \div 3+6 \times 5)$.
Perform division and multiplication first.

$$9 \div 3 = 3$$ $$6 \times 5 = 30$$

Substitute these values back into the parentheses.

$$3+30 = 33$$

Now, substitute this value back into the square brackets.

$$[33 \div 11] = 3$$

First, simplify the first set of parentheses $(4+5-6)$.

$$4+5-6 = 9-6 = 3$$

Next, simplify the second set of parentheses $(18-3 \times 4)$.
Perform multiplication first.

$$3 \times 4 = 12$$

Substitute this value back into the parentheses.

$$18-12 = 6$$

Now, substitute these values back into the square brackets.

$$[3+6] = 9$$

The original expression is $(3+4-6 \div 2+2) + [(9 \div 3+6 \times 5) \div 11] \times [(4+5-6) + (18-3 \times 4)] \div 9$.
Using the results from Step 1, Step 2, and Step 3, the expression becomes:

$$6 + 3 \times 9 \div 9$$

First, perform the multiplication.

$$3 \times 9 = 27$$

The expression becomes:

$$6 + 27 \div 9$$

Next, perform the division.

$$27 \div 9 = 3$$

The expression becomes:

$$6 + 3$$

Finally, perform the addition.

$$6+3 = 9$$

The simplified expression is:

$$9$$