Solve the following expression: (3+4-6÷2+2)+[(9÷3+6×5)÷11]×[(4+5-6)+(18-3×4)]÷9=

Step 1: Simplify the first set of parentheses $(3+4-6 \div 2+2)$. First, perform the division. $3+4-6 \div 2+2 = 3+4-3+2$ Next, perform additions and subtractions from left to right. $3+4-3+2 = 7-3+2 = 4+2 = 6$

Step 2: Simplify the first set of square brackets $[(9 \div 3+6 \times 5) \div 11]$. First, simplify the innermost parentheses $(9 \div 3+6 \times 5)$. Perform division and multiplication first. $9 \div 3 = 3$ $6 \times 5 = 30$ Substitute these values back into the parentheses. $3+30 = 33$ Now, substitute this value back into the square brackets. $[33 \div 11] = 3$

Step 3: Simplify the second set of square brackets $[(4+5-6) + (18-3 \times 4)]$. First, simplify the first set of parentheses $(4+5-6)$. $4+5-6 = 9-6 = 3$ Next, simplify the second set of parentheses $(18-3 \times 4)$. Perform multiplication first. $3 \times 4 = 12$ Substitute this value back into the parentheses. $18-12 = 6$ Now, substitute these values back into the square brackets. $[3+6] = 9$

Step 4: Substitute all simplified parts back into the original expression. The original expression is $(3+4-6 \div 2+2) + [(9 \div 3+6 \times 5) \div 11] \times [(4+5-6) + (18-3 \times 4)] \div 9$. Using the results from Step 1, Step 2, and Step 3, the expression becomes: $6 + 3 \times 9 \div 9$

Step 5: Perform multiplication and division from left to right. First, perform the multiplication. $3 \times 9 = 27$ The expression becomes: $6 + 27 \div 9$ Next, perform the division. $27 \div 9 = 3$ The expression becomes: $6 + 3$ Finally, perform the addition. $6+3 = 9$

The simplified expression is: $\boxed{9}$