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Solve the following geometry problems involving parallel lines and transversals, expressing relationships between angles: a) Given angles A4 = a and B1 = 6p, find the equation relating a and p. b) Giv

Mathematics

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Answers

2 parts
a

a+6p=180∘a + 6p = 180^\circ

b

a=90∘a = 90^\circ

Step-by-step solution

8 steps

here are the solutions for the geometry problems:

Part a· 4 steps

  1. Identify parallel lines and transversal.

    Lines CD and EF are parallel, indicated by the arrows on the lines. Line GH is the transversal intersecting these parallel lines.

  2. Identify the given angles and their positions.

    Angle A4A_4 is labeled as aa. This is the bottom-left interior angle at intersection A.
    Angle B1B_1 is labeled as 6p6p. This is the top-left interior angle at intersection B.

  3. Apply the property of consecutive interior angles.

    When two parallel lines are intersected by a transversal, consecutive interior angles (angles on the same side of the transversal and between the parallel lines) are supplementary, meaning they add up to 180∘180^\circ. Angles A4A_4 and B1B_1 are consecutive interior angles.

  4. Formulate the relationship between aa and pp.

    Therefore, we have:

    A4+B1=180∘A_4 + B_1 = 180^\circ

    Substituting the given expressions:

    a+6p=180∘\boxed{a + 6p = 180^\circ}

Part b

a=90∘a = 90^\circ

  1. Identify parallel lines and transversal.

    Lines CD and EF are parallel, indicated by the arrows on the lines. Line GH is the transversal intersecting these parallel lines.

  2. Identify the given angles and their positions.

    Angle A2A_2 is marked with a square symbol, which indicates a right angle. So, A2=90∘A_2 = 90^\circ. This is the top-right angle at intersection A.
    Angle B2B_2 is labeled as aa. This is the top-right angle at intersection B.

  3. Apply the property of corresponding angles.

    When two parallel lines are intersected by a transversal, corresponding angles (angles in the same relative position at each intersection) are equal. Angles A2A_2 and B2B_2 are corresponding angles.

  4. Solve for aa.

    Therefore, we have:

    A2=B2A_2 = B_2

    Substituting the given value:

    90∘=a90^\circ = a a=90∘\boxed{a = 90^\circ}
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