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Solve the following problems: 11 − 2x = 4, and find the value of x given two parallel lines intersected by a transversal with angles 55 and x.

Mathematics

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2) Solve.

11−2x=411 - 2x = 4
  1. Subtract 11 from both sides of the equation.

    −2x=4−11-2x = 4 - 11 −2x=−7-2x = -7
  2. Divide both sides by −2-2.

    x=−7−2x = \frac{-7}{-2} x=72x = \frac{7}{2} x=3.5x = 3.5

    The value of xx is 3.5\boxed{\textbf{3.5}}.

    3) Find the value of xx.
    The diagram shows two parallel lines intersected by a transversal. The angle 55∘55^\circ and the angle x∘x^\circ are consecutive interior angles (also known as same-side interior angles). When two parallel lines are intersected by a transversal, consecutive interior angles are supplementary, meaning their sum is 180∘180^\circ.

  3. Set up the equation based on the property of consecutive interior angles.

    x∘+55∘=180∘x^\circ + 55^\circ = 180^\circ
  4. Solve for xx.

    x=180−55x = 180 - 55 x=125x = 125

    The value of xx is 125\boxed{\textbf{125}}.

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