Solve the following linear equations: 1) 3x = 2x + 18, 2) 5t − 3 = 3t − 5, 4) 4z + 3 = 6 + 2z, 5) 2x − 1 = 14 − x

$$3x - 2x = 18$$ $$x = 18$$

The solution is $\boxed{x = 18}$.

प्रश्न 2:

$$5t - 3 = 3t - 5$$

$$5t - 3t - 3 = -5$$ $$2t - 3 = -5$$

$$2t = -5 + 3$$ $$2t = -2$$

$$t = \frac{-2}{2}$$ $$t = -1$$

The solution is $\boxed{t = -1}$.

प्रश्न 4:

$$4z + 3 = 6 + 2z$$

$$4z - 2z + 3 = 6$$ $$2z + 3 = 6$$

$$2z = 6 - 3$$ $$2z = 3$$

$$z = \frac{3}{2}$$

The solution is $\boxed{z = \frac{3}{2}}$.

प्रश्न 5:

$$2x - 1 = 14 - x$$

$$2x + x - 1 = 14$$ $$3x - 1 = 14$$

$$3x = 14 + 1$$ $$3x = 15$$

$$x = \frac{15}{3}$$ $$x = 5$$

The solution is $\boxed{x = 5}$.