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Solve the following modulo problems using repeated addition: -45 mod 8, -13 mod 3.

Mathematics

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Answer

−45(mod8)=3-45 \pmod 8 = \text{3}

Here are the solutions for the modulo problems using repeated addition:

  1. -45 mod 8 To find −45(mod8)-45 \pmod 8, we add 8 to −45-45 repeatedly until the result is between 0 and 7. We need to add 8 at least ⌈458⌉=⌈5.625⌉=6\lceil \frac{45}{8} \rceil = \lceil 5.625 \rceil = 6 times.

    −45+(6×8)=−45+48=3-45 + (6 \times 8) = -45 + 48 = 3

    Therefore, −45(mod8)=3-45 \pmod 8 = \boxed{\text{3}}.

  2. -13 mod 3 To find $-

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