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Solve for the unknown in the following modular arithmetic equations:

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Part 6

Solve for the unknown in the following modular arithmetic equations:

Part a· 3 steps

3m−2≡1(mod3)3m - 2 \equiv 1 \pmod{3}

  1. Add 2 to both sides of the congruence.

    3m≡1+2(mod3)3m \equiv 1 + 2 \pmod{3} 3m≡3(mod3)3m \equiv 3 \pmod{3}

  2. Simplify the right side.

    Since 3≡0(mod3)3 \equiv 0 \pmod{3}, we have:

    3m≡0(mod3)3m \equiv 0 \pmod{3}

  3. Since 3m3m is always a multiple of 3, 3m≡0(mod3)3m \equiv 0 \pmod{3} is true for any integer

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