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Solve the following multiplication problems: (c) 4 × 4261 × 25 (d) 184 × 125

Mathematics

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Answers

2 parts
c
426100
d
23000

Step-by-step solution

8 steps

Here are the solutions for problems (c) and (d).

Part c· 4 steps

  1. Write down the given expression.

    The expression is:

    4×4261×254 \times 4261 \times 25
  2. Group the numbers for easier multiplication.

    We can group 4 and 25 together.

    (4×25)×4261(4 \times 25) \times 4261
  3. Perform the multiplication within the parentheses.

    4×25=1004 \times 25 = 100

    Substitute this value back into the expression:

    100×4261100 \times 4261
  4. Perform the final multiplication.

    Multiplying by 100 means adding two zeros to the end of the number.

    100×4261=426100100 \times 4261 = 426100

    The final answer is 426100\boxed{426100}.

Part d23000

  1. Write down the given expression.

    The expression is:

    184×125184 \times 125
  2. Rewrite 125 as a fraction involving 1000 for easier multiplication.

    We know that 125=10008125 = \frac{1000}{8}.
    So, the expression becomes:

    184×10008184 \times \frac{1000}{8}
  3. Divide 184 by 8.

    1848=23\frac{184}{8} = 23

    Substitute this value back into the expression:

    23×100023 \times 1000
  4. Perform the final multiplication.

    Multiplying by 1000 means adding three zeros to the end of the number.

    23×1000=2300023 \times 1000 = 23000

    The final answer is 23000\boxed{23000}.

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