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Solve the following problems: 6. Name the shape. 7. Expand 64359 using powers. ACTIVITY TWO: 1. Multiply 536 by 23 using the lattice method.

Mathematics

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Here are the solutions to the problems:

6. Name the shape.

  1. Observe the properties of the given shape.

    The shape is a quadrilateral (4 sides). It has one pair of parallel sides (the top and bottom sides). It also has two right angles.

  2. Identify the shape based on its properties.

    A quadrilateral with exactly one pair of parallel sides is a trapezoid (or trapezium). Since it also has two right angles, it is a right trapezoid.
    The shape is a Right Trapezoid\boxed{\text{Right Trapezoid}}.

    7. Expand 64359 using powers.

  3. Break down the number into its place values.

    64359=60000+4000+300+50+964359 = 60000 + 4000 + 300 + 50 + 9

  4. Express each place value as a product of its digit and a power of 10.

    64359=(6×104)+(4×103)+(3×102)+(5×101)+(9×100)64359 = (6 \times 10^4) + (4 \times 10^3) + (3 \times 10^2) + (5 \times 10^1) + (9 \times 10^0)

    The expanded form is 6×104+4×103+3×102+5×101+9×100\boxed{6 \times 10^4 + 4 \times 10^3 + 3 \times 10^2 + 5 \times 10^1 + 9 \times 10^0}.

    ACTIVITY TWO

    1. Multiply 536 by 23 using the lattice method.

  5. Draw a lattice grid with 3 columns for 5, 3, 6 and 2 rows for 2, 3.

  6. Multiply each digit of 536 by each digit of 23 and write the products in the corresponding cells, splitting the tens and units diagonally.

    \multicolumn1c\multicolumn1c5\multicolumn1c3\multicolumn1c6\cline2−521/00/61/2\cline2−531/50/91/8\cline2−5\begin{array}{c|c|c|c} \multicolumn{1}{c}{} & \multicolumn{1}{c}{5} & \multicolumn{1}{c}{3} & \multicolumn{1}{c}{6} \\ \cline{2-5} 2 & 1/0 & 0/6 & 1/2 \\ \cline{2-5} 3 & 1/5 & 0/9 & 1/8 \\ \cline{2-5} \end{array}
  7. Sum the numbers along the diagonals, starting from the bottom right.

    Carry over any tens to the next diagonal sum.

    • Rightmost diagonal: 8
    • Next diagonal: 2+1+9=122 + 1 + 9 = 12 (write 2, carry 1)
    • Next diagonal: 6+0+5+1(carry)=126 + 0 + 5 + 1 (\text{carry}) = 12 (write 2, carry 1)
    • Next diagonal: 0+1+1(carry)=20 + 1 + 1 (\text{carry}) = 2
    • Leftmost diagonal: 1
  8. Read the digits from top left to bottom right.

    The product is 12328\boxed{12328}.

    2. Shade the following
    Note: No diagrams are provided, so the instructions for shading are given.

    a) A - B
    To shade A−BA - B (also written as A∖BA \setminus B), you would shade the region that contains all elements that are in set A but are not in set B. In a Venn diagram with two overlapping circles A and B, this means shading only the part of circle A that does not overlap with circle B.

    b) (M ∩\cap K)'
    To shade (M∩K)′(M \cap K)', you would shade the complement of the intersection of sets M and K. This means shading all elements that are not in the intersection of M and K. In a Venn diagram with two overlapping circles M and K, this means shading everything except the region where M and K overlap. This includes the parts of M and K that do not overlap, and any region outside both circles within the universal set.

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