Solve the following problems by filling in the missing numbers in the triangles.

The pattern for these problems is to multiply the two bottom numbers and then divide by the top number to get the number inside the triangle. Let $B_L$ be the bottom left number, $B_R$ be the bottom right number, and $T$ be the top number. The number inside the box, $I$, is calculated as: $I = (B_L \times B_R) \div T$ If a bottom number is missing, say $B_L$, the formula can be rearranged to: $B_L = (I \times T) \div B_R$

1. For $B_L = 14$, $B_R = 3$, $T = 6$: $I = (14 \times 3) \div 6$ $I = 42 \div 6$ $I = \boxed{\text{7}}$ Your calculation and answer are correct.

2. For $B_L = 5$, $B_R = 1$, $T = 20$: $I = (5 \times 1) \div 20$ $I = 5 \div 20$ $I = \boxed{\frac{1}{4}}$ Your calculation and answer are incorrect.

3. For $I = 21$, $B_R = 7$, $T = 3$ (finding $B_L$): $B_L = (21 \times 3) \div 7$ $B_L = 63 \div 7$ $B_L = \boxed{\text{9}}$ Your calculation and answer are correct.

4. For $I = \frac{1}{2}$, $B_R = 8$, $T = 2$ (finding $B_L$): $B_L = \left(\frac{1}{2} \times 2\right) \div 8$ $B_L = 1 \div 8$ $B_L = \boxed{\frac{1}{8}}$ Your work is incomplete.

5. For $B_L = 4$, $B_R = 4$, $T = 2$: $I = (4 \times 4) \div 2$ $I = 16 \div 2$ $I = \boxed{\text{8}}$ Your calculation is correct, but the answer is not filled in.

6. For $B_L = 4$, $B_R = 2$, $T = 10$: $I = (4 \times 2) \div 10$ $I = 8 \div 10$ $I = \boxed{\frac{4}{5}}$ Your calculation is incorrect.

7. For $B_L = \frac{1}{3}$, $B_R = 27$, $T = 3$: $I = \left(\frac{1}{3} \times 27\right) \div 3$ $I = 9 \div 3$ $I = \boxed{\text{3}}$ Your calculation is incorrect.

8. For $I = 6$, $B_R = 12$, $T = 16$ (finding $B_L$): $B_L = (6 \times 16) \div 12$ $B_L = 96 \div 12$ $B_L = \boxed{\text{8}}$ Your calculation is correct, but the answer is not filled in.

9. For $B_L = 13$, $B_R = 5$, $T = 13$: $I = (13 \times 5) \div 13$ $I = 65 \div 13$ $I = \boxed{\text{5}}$ Your calculation is correct, but the answer is not filled in.

10. For $B_L = \frac{1}{2}$, $B_R = 4$, $T = 2$: $I = \left(\frac{1}{2} \times 4\right) \div 2$ $I = 2 \div 2$ $I = \boxed{\text{1}}$ Your calculation is correct, but the answer is not filled in.