Look carefully at the triangles shown. Add up the angles inside each triangle and write the answer in the box next to each triangle. Fill in the size of each angle in the triangles below.

The tick marks on sides AB and AC indicate that $\triangle ABC$ is an **isosceles triangle**, meaning sides AB and AC are equal. In an isosceles triangle, the angles opposite the equal sides are also equal.  
Therefore, $\angle C = \angle B$.

Given $\angle B = 30^\circ$.  
So, $\angle C = 30^\circ$.

The sum of angles in a triangle is $180^\circ$.
$$
\angle A + \angle B + \angle C = 180^\circ
$$
$$
\angle A + 30^\circ + 30^\circ = 180^\circ
$$
$$
\angle A + 60^\circ = 180^\circ
$$
$$
\angle A = 180^\circ - 60^\circ
$$
$$
\angle A = 120^\circ
$$
The angles are: $\angle A = \boxed{120^\circ}$, $\angle B = \boxed{30^\circ}$, $\angle C = \boxed{30^\circ}$.

The sum of angles in a triangle is $180^\circ$.
$$
\angle P + \angle Q + \angle R = 180^\circ
$$
Given $\angle P = 70^\circ$ and $\angle Q = 40^\circ$.
$$
70^\circ + 40^\circ + \angle R = 180^\circ
$$
$$
110^\circ + \angle R = 180^\circ
$$
$$
\angle R = 180^\circ - 110^\circ
$$
$$
\angle R = 70^\circ
$$
The angles are: $\angle P = \boxed{70^\circ}$, $\angle Q = \boxed{40^\circ}$, $\angle R = \boxed{70^\circ}$.