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If 15 men take 12 days to build a certain type of house, how long would 18 men take to build the same type of house? 2. At a speed of 18 km/h, Shafa takes 30 minutes to ride his bike to school. How long would he take at a speed of:

Mathematics

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Here are the solutions for the problems.

1. House Construction

This is an inverse proportion problem, meaning that as the number of men increases, the time taken to build the house decreases. The total amount of work (man-days) remains constant.

  1. Calculate the total work in "man-days".

    Given that 15 men take 12 days to build a house:

    Total work=Number of men×Number of days\text{Total work} = \text{Number of men} \times \text{Number of days} Total work=15 men×12 days=180 man-days\text{Total work} = 15 \text{ men} \times 12 \text{ days} = 180 \text{ man-days}
  2. Calculate the time it would take for 8 men.

    To find out how long 8 men would take, divide the total work by the new number of men:

    Time=Total workNumber of men=180 man-days8 men=22.5 days\text{Time} = \frac{\text{Total work}}{\text{Number of men}} = \frac{180 \text{ man-days}}{8 \text{ men}} = 22.5 \text{ days}

    It would take 22.5 days for 8 men to build the same type of house.

    2. Shafa's Bike Ride

    First, we need to find the distance to Shafa's school using the initial speed and time. Then, we can calculate the time taken for different speeds.

  3. Calculate the distance to school.

    Shafa's initial speed is 18 km/h and the time taken is 30 minutes. Convert 30 minutes to hours:

    30 minutes=3060 hours=0.5 hours30 \text{ minutes} = \frac{30}{60} \text{ hours} = 0.5 \text{ hours}

    Now, calculate the distance using the formula Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}:

    Distance=18 km/h×0.5 hours=9 km\text{Distance} = 18 \text{ km/h} \times 0.5 \text{ hours} = 9 \text{ km}

    The distance to Shafa's school is 9 km.

    Now, calculate the time taken at different speeds:

    a) At a speed of 9 km/h:

    Time=DistanceSpeed=9 km9 km/h=1 hour\text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{9 \text{ km}}{9 \text{ km/h}} = 1 \text{ hour}

    This is equivalent to 1×60=601 \times 60 = 60 minutes.
    It would take 1 hour (or 60 minutes) at 9 km/h.

    b) At a speed of 20 km/h:

    Time=DistanceSpeed=9 km20 km/h=0.45 hours\text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{9 \text{ km}}{20 \text{ km/h}} = 0.45 \text{ hours}

    To convert to minutes: 0.45 hours×60 minutes/hour=27 minutes0.45 \text{ hours} \times 60 \text{ minutes/hour} = 27 \text{ minutes}.
    It would take 0.45 hours (or 27 minutes) at 20 km/h.

    c) At a speed of 14 km/h:

    Time=DistanceSpeed=9 km14 km/h≈0.6428 hours\text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{9 \text{ km}}{14 \text{ km/h}} \approx 0.6428 \text{ hours}

    To convert to minutes: 0.6428 hours×60 minutes/hour≈38.57 minutes0.6428 \text{ hours} \times 60 \text{ minutes/hour} \approx 38.57 \text{ minutes}.
    It would take approximately 0.64 hours (or 38.57 minutes) at 14 km/h.

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