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Solve the following problems using the indicated strategy.

Mathematics

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Here are the solutions to the problems:

1.

  1. Calculate the amount of raw material used in the first step.

    Material in first step=25×500 kg\text{Material in first step} = \frac{2}{5} \times 500 \text{ kg} Material in first step=10005 kg=200 kg\text{Material in first step} = \frac{1000}{5} \text{ kg} = 200 \text{ kg}
  2. Calculate the amount of raw material used in the second step.

    Material in second step=35×500 kg\text{Material in second step} = \frac{3}{5} \times 500 \text{ kg} Material in second step=15005 kg=300 kg\text{Material in second step} = \frac{1500}{5} \text{ kg} = 300 \text{ kg}

    The company uses 200 kg200 \text{ kg} in the first step and 300 kg300 \text{ kg} in the second step.

    The amount of raw material used in each step is First step: 200 kg, Second step: 300 kg\boxed{\text{First step: } 200 \text{ kg, Second step: } 300 \text{ kg}}.

    2.

  3. Mary has 14\frac{1}{4} of a cake.

    She gives half of this amount to her sister. To find the fraction her sister receives, multiply Mary's fraction by 12\frac{1}{2}.

    Fraction for sister=14×12\text{Fraction for sister} = \frac{1}{4} \times \frac{1}{2}
  4. Multiply the numerators and the denominators.

    Fraction for sister=1×14×2=18\text{Fraction for sister} = \frac{1 \times 1}{4 \times 2} = \frac{1}{8}

    Mary's sister receives 18\frac{1}{8} of the cake.

    The fraction of the cake her sister receives is 18\boxed{\frac{1}{8}}.

    3.

  5. Royce bought 20 t-shirts.

    The fraction of large size t-shirts is 35\frac{3}{5}. To find the number of large t-shirts, multiply the total number of t-shirts by this fraction.

    Number of large t-shirts=35×20\text{Number of large t-shirts} = \frac{3}{5} \times 20
  6. Perform the multiplication.

    Number of large t-shirts=3×205=605=12\text{Number of large t-shirts} = \frac{3 \times 20}{5} = \frac{60}{5} = 12

    Royce bought 12 large size t-shirts.

    The number of large size t-shirts Royce bought is 12\boxed{12}.

    4.

  7. Calculate the earnings for the first three days to identify the pattern.

    Day 1: 13×P150.00=P50.00\frac{1}{3} \times \text{P}150.00 = \text{P}50.00
    Day 2: 23×P300.00=P200.00\frac{2}{3} \times \text{P}300.00 = \text{P}200.00
    Day 3: 43×P600.00=P800.00\frac{4}{3} \times \text{P}600.00 = \text{P}800.00

  8. Observe the pattern in the multipliers and the base amounts.

    The numerator of the fraction doubles each day (1→2→41 \to 2 \to 4).
    The base amount doubles each day (P150→P300→P600\text{P}150 \to \text{P}300 \to \text{P}600).

  9. Apply the pattern to find the earnings for the 4th day.

    For Day 4, the numerator will be 4×2=84 \times 2 = 8, so the fraction is 83\frac{8}{3}.
    For Day 4, the base amount will be P600×2=P1200.00\text{P}600 \times 2 = \text{P}1200.00.

  10. Calculate the earnings for the 4th day.

    Earnings for Day 4=83×P1200.00\text{Earnings for Day 4} = \frac{8}{3} \times \text{P}1200.00 Earnings for Day 4=8×P1200.003=8×P400.00=P3200.00\text{Earnings for Day 4} = 8 \times \frac{\text{P}1200.00}{3} = 8 \times \text{P}400.00 = \text{P}3200.00

    Her daughter earned P3200.00 for the 4th day's work.

    The amount her daughter earned for the 4th day's work is P3200.00\boxed{\text{P}3200.00}.

    5.

  11. Calculate the fraction of red and yellow clips.

    Fraction red = 14\frac{1}{4}
    Fraction yellow = 14\frac{1}{4}
    Total fraction of red and yellow = 14+14=24=12\frac{1}{4} + \frac{1}{4} = \frac{2}{4} = \frac{1}{2}

  12. Calculate the fraction of blue clips.

    The remaining clips are blue.
    Fraction blue = 1−Fraction of red and yellow1 - \text{Fraction of red and yellow}
    Fraction blue = 1−12=121 - \frac{1}{2} = \frac{1}{2}

  13. Calculate the number of blue clips from the total of 60 clips.

    Number of blue clips=12×60\text{Number of blue clips} = \frac{1}{2} \times 60 Number of blue clips=30\text{Number of blue clips} = 30

    There are 30 blue clips.

    The number of blue clips is 30\boxed{30}.

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