Solve the following questions: 1a. Add 43501, 3450, 120, and 2. 1b. Subtract 4564 from 6000. 3. Find the LCM of 6, 8, 12. 4. Find the HCF of 10, 15, 25. 5. Based on a bar chart, how much was sold on M

Add the given numbers:

The sum is $\boxed{47073}$.

Subtract 4564 from 6000:

The difference is $\boxed{1436}$.

First, find the prime factorization of each number:
$6 = 2 \times 3$
$8 = 2 \times 2 \times 2 = 2^3$
$12 = 2 \times 2 \times 3 = 2^2 \times 3$
To find the LCM, take the highest power of each prime factor present in any of the numbers:
Highest power of 2 is $2^3$.
Highest power of 3 is $3^1$.
Multiply these highest powers:
$\text{LCM} = 2^3 \times 3^1 = 8 \times 3 = 24$.
The LCM is $\boxed{24}$.

First, find the prime factorization of each number:
$10 = 2 \times 5$
$15 = 3 \times 5$
$25 = 5 \times 5 = 5^2$
To find the HCF, identify the common prime factors and take the lowest power of each common factor:
The only common prime factor is 5. The lowest power of 5 common to all is $5^1$.
$\text{HCF} = 5$.
The HCF is $\boxed{5}$.

The y-axis represents the amount sold in FRS.

i) Monday: The bar for Monday reaches 5000 FRS.
He sold $\boxed{5000 \text{ FRS}}$ on Monday.

ii) Tuesday: The bar for Tuesday reaches 4000 FRS.
He sold $\boxed{4000 \text{ FRS}}$ on Tuesday.

iii) Wednesday: The bar for Wednesday reaches halfway between 5000 FRS and 6000 FRS, which is 5500 FRS.
He sold $\boxed{5500 \text{ FRS}}$ on Wednesday.

iv) Thursday: The bar for Thursday reaches halfway between 2000 FRS and 3000 FRS, which is 2500 FRS.
He sold $\boxed{2500 \text{ FRS}}$ on Thursday.

v) Friday: The bar for Friday reaches 6000 FRS.
He sold $\boxed{6000 \text{ FRS}}$ on Friday.

vi) How much did he sell throughout the week?
Add the sales from Monday to Friday:

He sold $\boxed{23000 \text{ FRS}}$ throughout the week.

vii) On which days did he not sell?
The bars for Saturday and Sunday are at 0 FRS, indicating no sales.
He did not sell on $\boxed{\text{Saturday and Sunday}}$.