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Solve the following simultaneous equations by elimination method. a) x+y=7; b) 3x+2y=8; c) x−y=3; d) x+y=4

Mathematics

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Step-by-step solution

4 steps

To find (x+y)(x+y) from the given system of equations:

  1. 2x−5y=−62x - 5y = -6
  2. 4x−3y=−124x - 3y = -12
  1. Multiply equation (1) by 2 to make the coefficients of xx equal.

    2(2x−5y)=2(−6)2(2x - 5y) = 2(-6) 4x−10y=−12(3)4x - 10y = -12 \quad (3)
  2. Subtract equation (2) from equation (3) to eliminate xx.

    (4x−10y)−(4x−3y)=−12−(−12)(4x - 10y) - (4x - 3y) = -12 - (-12) 4x−10y−4x+3y=−12+124x - 10y - 4x + 3y = -12 + 12 −7y=0-7y = 0 y=0y = 0
  3. Substitute the value of yy into equation (1) to solve for xx.

    2x−5(0)=−62x - 5(0) = -6 2x−0=−62x - 0 = -6 2x=−62x = -6 x=−62x = \frac{-6}{2} x=−3x = -3
  4. Calculate the value of (x+y)(x+y).

    x+y=−3+0x+y = -3 + 0 x+y=−3x+y = -3

    The final answer is −3\boxed{-3}.

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