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Solve the following word problems: 1. Sameer has 465 toffees... 2. A cup is 1/4 full of milk... 3. Ali divide 2 fruit cake equally among 6 persons...

Mathematics

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1. Sameer has 465 toffees that he wants to distribute on his birthday. He distributes 1/51/5 of these in the class. Out of the remaining toffees, he distributes 2/32/3 to his teachers. What is the number of toffees remaining with him?

  1. Calculate toffees distributed to the class.

    Toffees to class=15×465=93\text{Toffees to class} = \frac{1}{5} \times 465 = 93
  2. Calculate remaining toffees after distributing to the class.

    Remaining toffees=465−93=372\text{Remaining toffees} = 465 - 93 = 372
  3. Calculate toffees distributed to teachers from the remaining.

    Toffees to teachers=23×372=2×124=248\text{Toffees to teachers} = \frac{2}{3} \times 372 = 2 \times 124 = 248
  4. Calculate the final number of toffees remaining with Sameer.

    Toffees remaining=372−248=124\text{Toffees remaining} = 372 - 248 = 124

    The number of toffees remaining with Sameer is 124 toffees\boxed{\text{124 toffees}}.

    2. A cup is 1/41/4 full of milk. What part of the cup is still to be filled by milk make it full?

  5. Represent the full cup as 1.

  6. Subtract the filled portion from the total to find the part to be filled.

    Part to be filled=1−14=44−14=34\text{Part to be filled} = 1 - \frac{1}{4} = \frac{4}{4} - \frac{1}{4} = \frac{3}{4}

    The part of the cup still to be filled is 34\boxed{\frac{3}{4}}.

    3. Ali divide 2 fruit cake equally among 6 persons. What part of the cake he gave to each persons?

  7. Divide the total number of cakes by the number of persons.

    Part of cake per person=2 cakes6 persons\text{Part of cake per person} = \frac{2 \text{ cakes}}{6 \text{ persons}}
  8. Simplify the fraction.

    Part of cake per person=26=13\text{Part of cake per person} = \frac{2}{6} = \frac{1}{3}

    Ali gave 13 of a cake\boxed{\frac{1}{3} \text{ of a cake}} to each person.

    4. Rajesh purchased 2kg 500gms Potatoes, 300 gms of dhania, 6Kg 300gms Onion, 500gm palak & 2Kg 600gms tomatoes. Find the total weight of his Purchases in Kilograms?

  9. Convert all weights to kilograms (1 kg = 1000 g).

    Potatoes=2 kg 500 g=2.5 kg\text{Potatoes} = 2 \text{ kg } 500 \text{ g} = 2.5 \text{ kg} Dhania=300 g=0.3 kg\text{Dhania} = 300 \text{ g} = 0.3 \text{ kg} Onion=6 kg 300 g=6.3 kg\text{Onion} = 6 \text{ kg } 300 \text{ g} = 6.3 \text{ kg} Palak=500 g=0.5 kg\text{Palak} = 500 \text{ g} = 0.5 \text{ kg} Tomatoes=2 kg 600 g=2.6 kg\text{Tomatoes} = 2 \text{ kg } 600 \text{ g} = 2.6 \text{ kg}
  10. Sum all the weights.

    Total weight=2.5+0.3+6.3+0.5+2.6=12.2 kg\text{Total weight} = 2.5 + 0.3 + 6.3 + 0.5 + 2.6 = 12.2 \text{ kg}

    The total weight of his purchases is 12.2 kg\boxed{\text{12.2 kg}}.

    5. A rectangle is divided into certain number of equal parts. If 20 of the parts so formed represent the fraction 1/51/5, find the number of parts in which the rectangle has been divided?

  11. Let the total number of parts be xx.

    Set up the proportion.

    20x=15\frac{20}{x} = \frac{1}{5}
  12. Solve for xx.

    x=20×5=100x = 20 \times 5 = 100

    The rectangle has been divided into 100 parts\boxed{\text{100 parts}}.

    6. The food we eat remains in the stomach for a maximum of 4 hours. For what fraction of a day, does it remain there?

  13. Determine the total number of hours in a day.

    Hours in a day=24 hours\text{Hours in a day} = 24 \text{ hours}
  14. Form a fraction of the time food remains in the stomach to the total hours in a day.

    Fraction=4 hours24 hours\text{Fraction} = \frac{4 \text{ hours}}{24 \text{ hours}}
  15. Simplify the fraction.

    Fraction=16\text{Fraction} = \frac{1}{6}

    The food remains in the stomach for 16\boxed{\frac{1}{6}} of a day.

    7. Mr. Rakesh got a job at the age of 23 years & he got retired from the job at the age of 60 years. What fraction of his age till retirement was he in the job?

  16. Calculate the duration Mr.

    Rakesh was in the job.

    Duration in job=60 years−23 years=37 years\text{Duration in job} = 60 \text{ years} - 23 \text{ years} = 37 \text{ years}
  17. The age till retirement is 60 years.

    Form the fraction.

    Fraction=Duration in jobAge till retirement=3760\text{Fraction} = \frac{\text{Duration in job}}{\text{Age till retirement}} = \frac{37}{60}

    The fraction of his age till retirement that he was in the job is 3760\boxed{\frac{37}{60}}.

    8. There are 12 dozen egg crates. 7/247/24 of them are rotten & 1/31/3 of them are to be sent back. How many crates can be used.

  18. Calculate the total number of crates.

    (1 dozen = 12)

    Total crates=12 dozen×12 crates/dozen=144 crates\text{Total crates} = 12 \text{ dozen} \times 12 \text{ crates/dozen} = 144 \text{ crates}
  19. Calculate the number of rotten crates.

    Rotten crates=724×144=7×6=42 crates\text{Rotten crates} = \frac{7}{24} \times 144 = 7 \times 6 = 42 \text{ crates}
  20. Calculate the number of crates to be sent back.

    Crates to be sent back=13×144=48 crates\text{Crates to be sent back} = \frac{1}{3} \times 144 = 48 \text{ crates}
  21. Calculate the total number of unusable crates.

    Total unusable crates=42+48=90 crates\text{Total unusable crates} = 42 + 48 = 90 \text{ crates}
  22. Calculate the number of usable crates.

    Usable crates=144−90=54 crates\text{Usable crates} = 144 - 90 = 54 \text{ crates}

    The number of crates that can be used is 54 crates\boxed{\text{54 crates}}.

    9. Megha read 25 pages of a book containing 200 pages. Lalita read 2/52/5 of the same book. Who read less?

  23. Determine the number of pages Megha read.

    Megha read=25 pages\text{Megha read} = 25 \text{ pages}
  24. Calculate the number of pages Lalita read.

    Lalita read=25×200 pages=2×40=80 pages\text{Lalita read} = \frac{2}{5} \times 200 \text{ pages} = 2 \times 40 = 80 \text{ pages}
  25. Compare the number of pages read by Megha and Lalita.

    Since 25 pages (Megha) < 80 pages (Lalita), Megha read less.
    Megha\boxed{\text{Megha}} read less.

    10. Kabir exercised for 3/63/6 of an hour, while Rohit exercised for 3/43/4 of an hour. Who exercised for a longer time?

  26. Simplify Kabir's exercise time.

    Kabir’s time=36 hour=12 hour\text{Kabir's time} = \frac{3}{6} \text{ hour} = \frac{1}{2} \text{ hour}
  27. Compare Kabir's time and Rohit's time.

    Kabir’s time=12 hour=24 hour\text{Kabir's time} = \frac{1}{2} \text{ hour} = \frac{2}{4} \text{ hour} Rohit’s time=34 hour\text{Rohit's time} = \frac{3}{4} \text{ hour}

    Since 34>24\frac{3}{4} > \frac{2}{4}, Rohit exercised for a longer time.
    Rohit\boxed{\text{Rohit}} exercised for a longer time.

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