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Solve the following word problems involving algebra and fractions.

Mathematics

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Answer

55 bars of lavender soap55 \text{ bars of lavender soap}

234 litres of orange juice2\frac{3}{4} \text{ litres of orange juice}

4 pencils4 \text{ pencils}

Step-by-step solution

13 steps

Here are the solutions to the word problems:

  1. Define the variables.

    Let ww be the number of lavender soap bars sold.
    Number of lemongrass soap bars sold = w−6w - 6.

  2. Formulate the equation using the given information that 49 bars of lemongrass soap were sold.

    w−6=49w - 6 = 49
  3. Solve for ww.

    w=49+6w = 49 + 6 w=55w = 55

    The shopkeeper sold 55 bars of lavender soap\boxed{55 \text{ bars of lavender soap}}.

  4. Define the variables.

    Amount of apple juice = 2142\frac{1}{4} litres.
    Amount of orange juice = dd litres.
    Total fruit punch = 5 litres.

  5. Formulate the equation.

    214+d=52\frac{1}{4} + d = 5
  6. Convert the mixed number to an improper fraction.

    214=2×4+14=942\frac{1}{4} = \frac{2 \times 4 + 1}{4} = \frac{9}{4}
  7. Substitute the fraction into the equation.

    94+d=5\frac{9}{4} + d = 5
  8. Solve for dd.

    d=5−94d = 5 - \frac{9}{4} d=5×44−94d = \frac{5 \times 4}{4} - \frac{9}{4} d=204−94d = \frac{20}{4} - \frac{9}{4} d=114d = \frac{11}{4}
  9. Convert the improper fraction back to a mixed number.

    d=234d = 2\frac{3}{4}

    Mr Henderson made 234 litres of orange juice\boxed{2\frac{3}{4} \text{ litres of orange juice}}.

  10. Define the variables.

    Let pp be the number of pencils Nick has.
    Number of pens Nick has = p+3p + 3.
    Total number of pencils and pens = 11.

  11. Formulate the equation.

    p+(p+3)=11p + (p + 3) = 11
  12. Simplify the equation.

    2p+3=112p + 3 = 11
  13. Solve for pp.

    2p=11−32p = 11 - 3 2p=82p = 8 p=82p = \frac{8}{2} p=4p = 4

    Nick has 4 pencils\boxed{4 \text{ pencils}}.

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