Solve for fraction remaining

Mathematics

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Answer

18\frac{1}{8}

Step-by-step solution

2 steps

The fraction remaining of a radioactive substance is the ratio of the final amount (NN) to the initial amount (N0N_0). It can be calculated using the formula:

Fraction remaining=NN0=(12)n\text{Fraction remaining} = \frac{N}{N_0} = \left(\frac{1}{2}\right)^{n}

where:

  • NN is the final amount of the substance remaining.
  • N0N_0 is the initial amount of the substance.
  • nn is the number of half-lives that have passed, calculated as n=tT1/2n = \frac{t}{T_{1/2}}.
  • tt is the total time elapsed.
  • T1/2T_{1/2} is the half-life of the substance.

Example:
A radioactive sample has a half-life of 5 years. What fraction of the original sample will remain after 15 years?

  1. Determine the number of half-lives (nn) that have passed.

    n=tT1/2n = \frac{t}{T_{1/2}} n=15 years5 years/half-life=3 half-livesn = \frac{15 \text{ years}}{5 \text{ years/half-life}} = 3 \text{ half-lives}
  2. Use the formula for the fraction remaining.

    Fraction remaining=(12)n\text{Fraction remaining} = \left(\frac{1}{2}\right)^{n} Fraction remaining=(12)3\text{Fraction remaining} = \left(\frac{1}{2}\right)^{3} Fraction remaining=12×12×12\text{Fraction remaining} = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} Fraction remaining=18\text{Fraction remaining} = \frac{1}{8}

    After 15 years, 18\boxed{\frac{1}{8}} of the original sample will remain.

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