Solve for question one to 9

Mathematics

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Here are the solutions for questions 1 to 9.

Part 1· 4 steps

2log⁡b4−23log⁡b8+log⁡b2=log⁡bx2 \log_b 4 - \frac{2}{3} \log_b 8 + \log_b 2 = \log_b x
  1. Apply the power rule clog⁡ba=log⁡b(ac)c \log_b a = \log_b (a^c) to the first two terms.

    log⁡b(42)−log⁡b(823)+log⁡b2=log⁡bx\log_b (4^2) - \log_b (8^{\frac{2}{3}}) + \log_b 2 = \log_b x log⁡b16−log⁡b(83)2+log⁡b2=log⁡bx\log_b 16 - \log_b (\sqrt[3]{8})^2 + \log_b 2 = \log_b x log⁡b16−log⁡b(22)+log⁡b2=log⁡bx\log_b 16 - \log_b (2^2) + \log_b 2 = \log_b x log⁡b16−log⁡b4+log⁡b2=log⁡bx\log_b 16 - \log_b 4 + \log_b 2 = \log_b x
  2. Apply the quotient rule log⁡bM−log⁡bN=log⁡b(MN)\log_b M - \log_b N = \log_b \left(\frac{M}{N}\right) to the first two terms.

    log⁡b(164)+log⁡b2=log⁡bx\log_b \left(\frac{16}{4}\right) + \log_b 2 = \log_b x log⁡b4+log⁡b2=log⁡bx\log_b 4 + \log_b 2 = \log_b x
  3. Apply the product rule log⁡bM+log⁡bN=log⁡b(M×N)\log_b M + \log_b N = \log_b (M \times N) to the left side.

    log⁡b(4×2)=log⁡bx\log_b (4 \times 2) = \log_b x log⁡b8=log⁡bx\log_b 8 = \log_b x
  4. Equate the arguments since the bases are the same.

    x=8\boxed{x = 8}

Part 2· 3 steps

2log⁡b3+log⁡b5−log⁡b9=log⁡bx2 \log_b 3 + \log_b 5 - \log_b 9 = \log_b x
  1. Apply the power rule clog⁡ba=log⁡b(ac)c \log_b a = \log_b (a^c) to the first term.

    log⁡b(32)+log⁡b5−log⁡b9=log⁡bx\log_b (3^2) + \log_b 5 - \log_b 9 = \log_b x log⁡b9+log⁡b5−log⁡b9=log⁡bx\log_b 9 + \log_b 5 - \log_b 9 = \log_b x
  2. Combine terms.

    (log⁡b9−log⁡b9)+log⁡b5=log⁡bx(\log_b 9 - \log_b 9) + \log_b 5 = \log_b x 0+log⁡b5=log⁡bx0 + \log_b 5 = \log_b x log⁡b5=log⁡bx\log_b 5 = \log_b x
  3. Equate the arguments.

    x=5\boxed{x = 5}

Part 3· 3 steps

log⁡b16−log⁡b2+log⁡b4=log⁡bx\log_b 16 - \log_b 2 + \log_b 4 = \log_b x
  1. Apply the quotient rule log⁡bM−log⁡bN=log⁡b(MN)\log_b M - \log_b N = \log_b \left(\frac{M}{N}\right) to the first two terms.

    log⁡b(162)+log⁡b4=log⁡bx\log_b \left(\frac{16}{2}\right) + \log_b 4 = \log_b x log⁡b8+log⁡b4=log⁡bx\log_b 8 + \log_b 4 = \log_b x
  2. Apply the product rule log⁡bM+log⁡bN=log⁡b(M×N)\log_b M + \log_b N = \log_b (M \times N) to the left side.

    log⁡b(8×4)=log⁡bx\log_b (8 \times 4) = \log_b x log⁡b32=log⁡bx\log_b 32 = \log_b x
  3. Equate the arguments.

    x=32\boxed{x = 32}

Part 4· 3 steps

log⁡b25+log⁡b4−log⁡b10=log⁡bx\log_b 25 + \log_b 4 - \log_b 10 = \log_b x
  1. Apply the product rule log⁡bM+log⁡bN=log⁡b(M×N)\log_b M + \log_b N = \log_b (M \times N) to the first two terms.

    log⁡b(25×4)−log⁡b10=log⁡bx\log_b (25 \times 4) - \log_b 10 = \log_b x log⁡b100−log⁡b10=log⁡bx\log_b 100 - \log_b 10 = \log_b x
  2. Apply the quotient rule log⁡bM−log⁡bN=log⁡b(MN)\log_b M - \log_b N = \log_b \left(\frac{M}{N}\right) to the left side.

    log⁡b(10010)=log⁡bx\log_b \left(\frac{100}{10}\right) = \log_b x log⁡b10=log⁡bx\log_b 10 = \log_b x
  3. Equate the arguments.

    x=10\boxed{x = 10}

Part 5· 3 steps

log⁡b12−log⁡b3+log⁡b2=log⁡bx\log_b 12 - \log_b 3 + \log_b 2 = \log_b x
  1. Apply the quotient rule log⁡bM−log⁡bN=log⁡b(MN)\log_b M - \log_b N = \log_b \left(\frac{M}{N}\right) to the first two terms.

    log⁡b(123)+log⁡b2=log⁡bx\log_b \left(\frac{12}{3}\right) + \log_b 2 = \log_b x log⁡b4+log⁡b2=log⁡bx\log_b 4 + \log_b 2 = \log_b x
  2. Apply the product rule log⁡bM+log⁡bN=log⁡b(M×N)\log_b M + \log_b N = \log_b (M \times N) to the left side.

    log⁡b(4×2)=log⁡bx\log_b (4 \times 2) = \log_b x log⁡b8=log⁡bx\log_b 8 = \log_b x
  3. Equate the arguments.

    x=8\boxed{x = 8}

Part 6· 3 steps

log⁡b100−log⁡b5+log⁡b2=log⁡bx\log_b 100 - \log_b 5 + \log_b 2 = \log_b x
  1. Apply the quotient rule log⁡bM−log⁡bN=log⁡b(MN)\log_b M - \log_b N = \log_b \left(\frac{M}{N}\right) to the first two terms.

    log⁡b(1005)+log⁡b2=log⁡bx\log_b \left(\frac{100}{5}\right) + \log_b 2 = \log_b x log⁡b20+log⁡b2=log⁡bx\log_b 20 + \log_b 2 = \log_b x
  2. Apply the product rule log⁡bM+log⁡bN=log⁡b(M×N)\log_b M + \log_b N = \log_b (M \times N) to the left side.

    log⁡b(20×2)=log⁡bx\log_b (20 \times 2) = \log_b x log⁡b40=log⁡bx\log_b 40 = \log_b x
  3. Equate the arguments.

    x=40\boxed{x = 40}

Part 7· 3 steps

log⁡b18+log⁡b2−log⁡b4=log⁡bx\log_b 18 + \log_b 2 - \log_b 4 = \log_b x
  1. Apply the product rule log⁡bM+log⁡bN=log⁡b(M×N)\log_b M + \log_b N = \log_b (M \times N) to the first two terms.

    log⁡b(18×2)−log⁡b4=log⁡bx\log_b (18 \times 2) - \log_b 4 = \log_b x log⁡b36−log⁡b4=log⁡bx\log_b 36 - \log_b 4 = \log_b x
  2. Apply the quotient rule log⁡bM−log⁡bN=log⁡b(MN)\log_b M - \log_b N = \log_b \left(\frac{M}{N}\right) to the left side.

    log⁡b(364)=log⁡bx\log_b \left(\frac{36}{4}\right) = \log_b x log⁡b9=log⁡bx\log_b 9 = \log_b x
  3. Equate the arguments.

    x=9\boxed{x = 9}

Part 8· 3 steps

log⁡b24−log⁡b3+log⁡b5=log⁡bx\log_b 24 - \log_b 3 + \log_b 5 = \log_b x
  1. Apply the quotient rule log⁡bM−log⁡bN=log⁡b(MN)\log_b M - \log_b N = \log_b \left(\frac{M}{N}\right) to the first two terms.

    log⁡b(243)+log⁡b5=log⁡bx\log_b \left(\frac{24}{3}\right) + \log_b 5 = \log_b x log⁡b8+log⁡b5=log⁡bx\log_b 8 + \log_b 5 = \log_b x
  2. Apply the product rule log⁡bM+log⁡bN=log⁡b(M×N)\log_b M + \log_b N = \log_b (M \times N) to the left side.

    log⁡b(8×5)=log⁡bx\log_b (8 \times 5) = \log_b x log⁡b40=log⁡bx\log_b 40 = \log_b x
  3. Equate the arguments.

    x=40\boxed{x = 40}

Part 9· 3 steps

log⁡b15+log⁡b2−log⁡b6=log⁡bx\log_b 15 + \log_b 2 - \log_b 6 = \log_b x
  1. Apply the product rule log⁡bM+log⁡bN=log⁡b(M×N)\log_b M + \log_b N = \log_b (M \times N) to the first two terms.

    log⁡b(15×2)−log⁡b6=log⁡bx\log_b (15 \times 2) - \log_b 6 = \log_b x log⁡b30−log⁡b6=log⁡bx\log_b 30 - \log_b 6 = \log_b x
  2. Apply the quotient rule log⁡bM−log⁡bN=log⁡b(MN)\log_b M - \log_b N = \log_b \left(\frac{M}{N}\right) to the left side.

    log⁡b(306)=log⁡bx\log_b \left(\frac{30}{6}\right) = \log_b x log⁡b5=log⁡bx\log_b 5 = \log_b x
  3. Equate the arguments.

    x=5\boxed{x = 5}
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