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Solve for x in the equation, 9^x+1 + 32x = 270

Mathematics

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Answer

32\frac{3}{2}

5
(1, 5)

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It looks like you've sent the same equation for question 11 again. I'll provide the solution for it once more, and then I'll address the partially visible question below it.

11. Solve for xx in the equation, 9x+1+32x=2709^{x+1} + 3^{2x} = 270

  1. Express all terms with the same base.

    Rewrite 9x+19^{x+1} as (32)x+1(3^2)^{x+1}.

    (32)x+1+32x=270(3^2)^{x+1} + 3^{2x} = 270 32(x+1)+32x=2703^{2(x+1)} + 3^{2x} = 270 32x+2+32x=2703^{2x+2} + 3^{2x} = 270
  2. Factor out the common term 32x3^{2x}.

    32x⋅32+32x=2703^{2x} \cdot 3^2 + 3^{2x} = 270 32x(32+1)=2703^{2x}(3^2 + 1) = 270 32x(9+1)=2703^{2x}(9 + 1) = 270 32x(10)=2703^{2x}(10) = 270
  3. Isolate the exponential term.

    32x=270103^{2x} = \frac{270}{10} 32x=273^{2x} = 27
  4. Express the right side with the same base as the left side.

    Since 27=3327 = 3^3:

    32x=333^{2x} = 3^3
  5. Equate the exponents and solve for xx.

    2x=32x = 3 x=32x = \frac{3}{2}

    The value of xx is 32\boxed{\frac{3}{2}}.


    For the next question, the image shows:
    Given y=x2−2x+6y = x^2 - 2x + 6, find the...
    The rest of the question is cut off. Assuming the question asks for the minimum value of yy or the coordinates of the vertex of the parabola:

  6. Identify the coefficients of the quadratic equation.

    The equation is in the form y=ax2+bx+cy = ax^2 + bx + c, where a=1a=1, b=−2b=-2, and c=6c=6.
    Since a>0a > 0, the parabola opens upwards, meaning it has a minimum value at its vertex.

  7. Find the x-coordinate of the vertex.

    The x-coordinate of the vertex is given by the formula x=−b2ax = -\frac{b}{2a}.

    x=−−22(1)x = -\frac{-2}{2(1)} x=22x = \frac{2}{2} x=1x = 1
  8. Find the minimum value of yy (the y-coordinate of the vertex).

    Substitute the x-coordinate of the vertex (x=1x=1) back into the equation for yy.

    y=(1)2−2(1)+6y = (1)^2 - 2(1) + 6 y=1−2+6y = 1 - 2 + 6 y=5y = 5

    The minimum value of yy is 5\boxed{5}.
    The coordinates of the vertex are (1,5)\boxed{(1, 5)}.

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