Solve for x in the following algebra problems: a) x+7=15, b) -3x=-6, c) 9x−7=11, d) x/4=-5, e) -x/3+1=3, f) (3x-1)/2=2, g) x−8=19

$$x = 8$$

The solution is $\boxed{x=8}$.

$$x = 2$$

The solution is $\boxed{x=2}$.

$$9x = 11 + 7$$ $$9x = 18$$

$$x = 2$$

The solution is $\boxed{x=2}$.

$$x = -20$$

The solution is $\boxed{x=-20}$.

$$-\frac{x}{3} = 3 - 1$$ $$-\frac{x}{3} = 2$$

$$x = -6$$

The solution is $\boxed{x=-6}$.

$$3x-1 = 2 \times 2$$ $$3x-1 = 4$$

$$3x = 4 + 1$$ $$3x = 5$$

$$x = \frac{5}{3}$$

The solution is $\boxed{x=\frac{5}{3}}$.

$$x = 27$$

The solution is $\boxed{x=27}$.

$$3x = 29 - 5$$ $$3x = 24$$

$$x = 8$$

The solution is $\boxed{x=8}$.

$$m = 18$$

The solution is $\boxed{m=18}$.

j) Solve for $x$:

$$\frac{1}{2}(3x+1)+\frac{1}{3}(2x+10)=0$$

$$6 \cdot \frac{1}{2}(3x+1) + 6 \cdot \frac{1}{3}(2x+10) = 6 \cdot 0$$ $$3(3x+1) + 2(2x+10) = 0$$

$$(9x + 4x) + (3 + 20) = 0$$ $$13x + 23 = 0$$

$$x = -\frac{23}{13}$$

The solution is $\boxed{x=-\frac{23}{13}}$.