Solve for Y given the equation x = 3Y − 2 and x = 1.

The given equation is $x = 3Y - 2$.
We are given that $x = 1$. Substitute this value into the equation:

$$1 = 3Y - 2$$

Add 2 to both sides of the equation:

$$1 + 2 = 3Y - 2 + 2$$ $$3 = 3Y$$

Divide both sides by 3:

$$\frac{3}{3} = \frac{3Y}{3}$$ $$1 = Y$$

The value of $Y$ when $x=1$ is 1.

The final answer is $Y = 1$.