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Calculate the number of tablets Ethel has to receive for a complete course of promethazine 12.5mg bd for 3 days, given that the stock available is 25mg tablets.

Chemistry

ScanSolve AI Answer

Step-by-step solution

11 steps

Q(a)

  1. Formula for amount of drug remaining.

    A=A0(12)t/t1/2A = A_0 \left( \frac{1}{2} \right)^{t / t_{1/2}}
  2. Substitute given values (A0=12A_0 = 12 mg, t=5t = 5 h, t1/2=10t_{1/2} = 10 h).

    A=12(12)5/10A = 12 \left( \frac{1}{2} \right)^{5/10}
  3. Simplify exponent.

    A=12(12)0.5=12×2−0.5A = 12 \left( \frac{1}{2} \right)^{0.5} = 12 \times 2^{-0.5}
  4. Calculate 20.5=2≈1.4142^{0.5} = \sqrt{2} \approx 1.414.

    2−0.5=11.414≈0.7072^{-0.5} = \frac{1}{1.414} \approx 0.707
  5. Multiply.

    A≈12×0.707=8.5 mgA \approx 12 \times 0.707 = 8.5 \text{ mg}

    Final answer: 8.5 mg

    Q(b)

  6. Formula for mass of insulin.

    m=Ucm = \frac{U}{c}

    where UU is units, c=28.8c = 28.8 units/mg.

  7. Substitute U=35U = 35 units.

    m=3528.8m = \frac{35}{28.8}
  8. Divide.

    28.8×1.2=34.5628.8 \times 1.2 = 34.56 35−34.56=0.4435 - 34.56 = 0.44 0.44/28.8≈0.0150.44 / 28.8 \approx 0.015 m≈1.2+0.015=1.22 mgm \approx 1.2 + 0.015 = 1.22 \text{ mg}

    Final answer: 1.22 mg

    Q(c)

  9. Number of doses per day.

    24 h6 h/dose=4 doses/day\frac{24 \text{ h}}{6 \text{ h/dose}} = 4 \text{ doses/day}
  10. Tablets per dose (500 mg dose, 500 mg/tablet).

    1 tablet/dose1 \text{ tablet/dose}
  11. Total tablets per day.

    4 doses/day×1 tablet/dose=4 tablets/day4 \text{ doses/day} \times 1 \text{ tablet/dose} = 4 \text{ tablets/day}

    Final answer: 4 tablets/day

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