Calculate the number of tablets Ethel has to receive for a complete course of promethazine 12.5mg bd for 3 days, given that the stock available is 25mg tablets.

Chemistry
Calculate the number of tablets Ethel has to receive for a complete course of promethazine 12.5mg bd for 3 days, given that the stock available is 25mg tablets.

ScanSolve AI Answer

Answer

8.5 mg

Q(a)

Step 1: Formula for amount of drug remaining.

A=A0(12)t/t1/2A = A_0 \left( \frac{1}{2} \right)^{t / t_{1/2}}

Step 2: Substitute given values (A0=12A_0 = 12 mg, t=5t = 5 h, t1/2=10t_{1/2} = 10 h).

A=12(12)5/10A = 12 \left( \frac{1}{2} \right)^{5/10}

Step 3: Simplify exponent.

A=12(12)0.5=12×20.5A = 12 \left( \frac{1}{2} \right)^{0.5} = 12 \times 2^{-0.5}

Step 4: Calculate 20.5=21.4142^{0.5} = \sqrt{2} \approx 1.414.

20.5=11.4140.7072^{-0.5} = \frac{1}{1.414} \approx 0.707

Step 5: Multiply.

A12×0.707=8.5mgA \approx 12 \times 0.707 = 8.5 mg

Final answer: 8.5 \text{ mg}

Q(b)

Step 1: Formula for mass of insulin.

m=Ucm = \frac{U}{c}

where UU is units, c=28.8c = 28.8 units/mg.

Step 2: Substitute U=35U = 35 units.

m=3528.8m = \frac{35}{28.8}

Step 3: Divide.

28.8×1.2=34.5628.8 \times 1.2 = 34.56

3534.56=0.4435 - 34.56 = 0.44

0.44/28.80.0150.44 / 28.8 \approx 0.015

m1.2+0.015=1.22mgm \approx 1.2 + 0.015 = 1.22 mg

Final answer: 1.22 \text{ mg}

Q(c)

Step 1: Number of doses per day.

24h6h/dose=4doses/day\frac{24 h}{6 h/dose} = 4 doses/day

Step 2: Tablets per dose (500 mg dose, 500 mg/tablet).

1tablet/dose1 tablet/dose

Step 3: Total tablets per day.

4doses/day×1tablet/dose=4tablets/day4 doses/day \times 1 tablet/dose = 4 tablets/day

Final answer: 4 \text{ tablets/day}

Was this helpful?

Need help with your own homework?

Get instant step-by-step solutions to any question. Free to start.

Ask Your Question

Still have questions?

Quick Answer

Q(a) Step 1: Formula for amount of drug remaining. A = A_0 ( (1)/(2) )^t / t_1/2 Step 2: Substitute given values (A_0 = 12 mg, t = 5 h, t_1/2 = 10 h).

Calculate the number of tablets Ethel has to receive for a complete course of promethazine 12.5mg bd for 3 days, given that the stock available is 25mg tablets.
Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI Answer
Q(a) Step 1: Formula for amount of drug remaining. A = A_0 ( (1)/(2) )^t / t_1/2 Step 2: Substitute given values (A_0 = 12 mg, t = 5 h, t_1/2 = 10 h). A = 12 ( (1)/(2) )^5/10 Step 3: Simplify exponent. A = 12 ( (1)/(2) )^0.5 = 12 × 2^-0.5 Step 4: Calculate 2^0.5 = sqrt(2) ≈ 1.414. 2^-0.5 = (1)/(1.414) ≈ 0.707 Step 5: Multiply. A ≈ 12 × 0.707 = 8.5 mg Final answer: 8.5 mg Q(b) Step 1: Formula for mass of insulin. m = (U)/(c) where U is units, c = 28.8 units/mg. Step 2: Substitute U = 35 units. m = (35)/(28.8) Step 3: Divide. 28.8 × 1.2 = 34.56 35 - 34.56 = 0.44 0.44 / 28.8 ≈ 0.015 m ≈ 1.2 + 0.015 = 1.22 mg Final answer: 1.22 mg Q(c) Step 1: Number of doses per day. 24 h6 h/dose = 4 doses/day Step 2: Tablets per dose (500 mg dose, 500 mg/tablet). 1 tablet/dose Step 3: Total tablets per day. 4 doses/day × 1 tablet/dose = 4 tablets/day Final answer: 4 tablets/day