From a base camp R, two hikers P and Q start walking at the same time. P walks on a bearing of 205° at 5 km/h and Q walks on a bearing of 060° at 5 km/h. After 4 hours, find: a) the distance between P

P moves on a bearing of 205° from R. Q moves on a bearing of 060° from R. The angle $\angle PRQ$ between their paths from R is the difference between these bearings.

We have a triangle RPQ with sides $RP = 20$ km, $RQ = 15$ km, and the included angle $\angle PRQ = 145^\circ$.
The Cosine Rule states: $PQ^2 = RP^2 + RQ^2 - 2(RP)(RQ)\cos(\angle PRQ)$

Rounding to the nearest whole number:

To find the bearing of Q from P, we first need to determine an angle within $\triangle RPQ$. Let's find $\angle RPQ$.
The Sine Rule states: $\frac{RQ}{\sin(\angle RPQ)} = \frac{PQ}{\sin(\angle PRQ)}$

The bearing of P from R is 205°. The