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From the information provided, find the value of m and the number of people who speak only one language.

Mathematics

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Question 11:

b) Find the:

(i) value of mm;

(ii) number of people who speak one language only.

To solve this, we will use the information provided in the problem statement for Question 11, which was:
Total people = 50
Speak Yoruba (Y): (m2+3)(m^2 + 3)
Speak Hausa (H): (5m−3)(5m - 3)
Speak Igbo (I): (3m+1)(3m + 1)
Speak all three languages (Y ∩\cap H ∩\cap I): 4
Speak exactly two languages: 14
Those who speak Igbo and Yoruba only (Y ∩\cap I only) are half of those who speak Yoruba and Hausa only (Y ∩\cap H only).
Those who speak Hausa and Igbo only (H ∩\cap I only) are 1 less than those who speak Yoruba and Hausa only (Y ∩\cap H only).
6 of them could not speak any of the languages.


b) (i) Find the value of mm.

  1. Define variables for the 'exactly two languages' regions.

    Let xx be the number of people who speak Yoruba and Hausa only (Y∩H onlyY \cap H \text{ only}).
    From the problem statement:

    • Those who speak Igbo and Yoruba only (Y∩I onlyY \cap I \text{ only}) are half of those who speak Yoruba and Hausa only: Y∩I only=12xY \cap I \text{ only} = \frac{1}{2}x.
    • Those who speak Hausa and Igbo only (H∩I onlyH \cap I \text{ only}) are 1 less than those who speak Yoruba and Hausa only: H∩I only=x−1H \cap I \text{ only} = x - 1.
  2. Use the total number of people speaking exactly two languages to find xx.

    The problem states that 14 people speak exactly two languages.

    (Y∩H only)+(Y∩I only)+(H∩I only)=14(Y \cap H \text{ only}) + (Y \cap I \text{ only}) + (H \cap I \text{ only}) = 14 x+12x+(x−1)=14x + \frac{1}{2}x + (x - 1) = 14

    Combine like terms:

    2.5x−1=142.5x - 1 = 14

    Add 1 to both sides:

    2.5x=152.5x = 15

    Divide by 2.5:

    x=152.5=6x = \frac{15}{2.5} = 6

    So, the number of people speaking exactly two languages are:
    $Y \cap H

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