Find the GCD of 40, 80, and 100. Also, sum 468521, 524026, and 314632.

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To find the longest length of smaller cloth pieces of equal length, we need to find the Greatest Common Divisor (GCD) of 40 metres, 80 metres, and 100 metres.

Find the prime factorization of each length.
$40 = 2 \times 2 \times 2 \times 5 = 2^3 \times 5^1$ $80 = 2 \times 2 \times 2 \times 2 \times 5 = 2^4 \times 5^1$ $100 = 2 \times 2 \times 5 \times 5 = 2^2 \times 5^2$
Identify the common prime factors and their lowest powers.
The common prime factors are 2 and 5.
The lowest power of 2 is $2^2$ .
The lowest power of 5 is $5^1$ .
Multiply these lowest powers to find the GCD.
$\text{GCD}(40, 80, 100) = 2^2 \times 5^1 = 4 \times 5 = 20$
The longest length of the smaller cloth pieces is 20 metres.
1. To find the total number of people who walked in the three regions, we need to sum the number of people from each region.
Add the number of people from Region 1, Region 2, and Region 3.
$\text{Total people} = 468521 + 524026 + 314632$
Perform the addition.
$\text{Total people} = 1307179$
The total number of people who walked in the three regions is 1,307,179.

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