This biology question covers important biological concepts and processes. The step-by-step explanation below helps you understand the underlying mechanisms and reasoning.

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Step 1: Determine the genotypes of the parents. Haemophilia is an X-linked recessive disorder. Let X represent the allele for normal blood clotting and X represent the allele for haemophilia.
Step 2: Perform the genetic cross between John (XY) and Jane (XX). Possible gametes from John: X, Y Possible gametes from Jane: X, X
Punnett Square:
Step 3: Determine the genotypes of their children. The possible genotypes for their children are XX (normal female), XX (normal female carrier), XY (normal male), and XY (haemophiliac male).
They have a haemophiliac son. The genotype of the haemophiliac son is .
They have two daughters. Both daughters have normal blood clotting (as only the son is specified as haemophiliac). The possible genotypes for a daughter with normal blood clotting are XX or XX. Therefore, the genotypes of the two daughters are: Daughter 1: Daughter 2:
a) Colchicine is economically important because it is used in plant breeding to induce polyploidy, which is the multiplication of chromosome sets. This can lead to the development of new plant varieties with desirable traits such as increased fruit size, improved vigor, or sterility (e.g., seedless fruits and vegetables).
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Determine the genotypes of the parents. Haemophilia is an X-linked recessive disorder.
This biology question covers important biological concepts and processes. The step-by-step explanation below helps you understand the underlying mechanisms and reasoning.