Given a triangle with vertices at A(1,3), B(4,7) and C(6,2) it undergoes two successive translation first by vector V1 = (2/3) and second by vector V2 = (-4/-1). Find the final coordinate of the triangle and explain how the composition of these translation affect the overall position movement.

To find the overall translation, we add the two translation vectors $V_1$ and $V_2$.

For a point $(x, y)$ and a translation vector $\begin{pmatrix} a \\ b \end{pmatrix}$, the new point is $(x+a, y+b)$.

For vertex A(1, 3):

For vertex B(4, 7):

For vertex C(6, 2):

The final coordinates of the triangle are $\boxed{A'(-1, 12), B'(2, 16), C'(4, 11)}$.

The composition of two successive translations is equivalent to a single translation by the sum of the individual translation vectors. In this case, the triangle undergoes an overall translation by the vector $\begin{pmatrix} -2 \\ 9 \end{pmatrix}$. This means the entire triangle moves 2 units to the left and 9 units upwards from its original position.