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Given AB=(-4) and CA=(3/5), find BC.

Mathematics

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Answer

(1−2)\begin{pmatrix} 1 \\ -2 \end{pmatrix}

Step-by-step solution

5 steps
  1. Identify the given vectors.

    We are given the vectors AB⃗\vec{AB} and CA⃗\vec{CA}.

    AB⃗=(−47)\vec{AB} = \begin{pmatrix} -4 \\ 7 \end{pmatrix} CA⃗=(3−5)\vec{CA} = \begin{pmatrix} 3 \\ -5 \end{pmatrix}
  2. Express BC⃗\vec{BC} in terms of the given vectors.

    Using the triangle rule for vector addition, BC⃗=BA⃗+AC⃗\vec{BC} = \vec{BA} + \vec{AC}.
    We know that BA⃗=−AB⃗\vec{BA} = -\vec{AB} and AC⃗=−CA⃗\vec{AC} = -\vec{CA}.

  3. Calculate BA⃗\vec{BA}.

    BA⃗=−AB⃗=−(−47)=(−(−4)−(7))=(4−7)\vec{BA} = -\vec{AB} = -\begin{pmatrix} -4 \\ 7 \end{pmatrix} = \begin{pmatrix} -(-4) \\ -(7) \end{pmatrix} = \begin{pmatrix} 4 \\ -7 \end{pmatrix}
  4. Calculate AC⃗\vec{AC}.

    AC⃗=−CA⃗=−(3−5)=(−(3)−(−5))=(−35)\vec{AC} = -\vec{CA} = -\begin{pmatrix} 3 \\ -5 \end{pmatrix} = \begin{pmatrix} -(3) \\ -(-5) \end{pmatrix} = \begin{pmatrix} -3 \\ 5 \end{pmatrix}
  5. Calculate BC⃗\vec{BC}.

    Now, substitute the values of BA⃗\vec{BA} and AC⃗\vec{AC} into the expression for BC⃗\vec{BC}:

    BC⃗=BA⃗+AC⃗=(4−7)+(−35)\vec{BC} = \vec{BA} + \vec{AC} = \begin{pmatrix} 4 \\ -7 \end{pmatrix} + \begin{pmatrix} -3 \\ 5 \end{pmatrix} BC⃗=(4+(−3)−7+5)\vec{BC} = \begin{pmatrix} 4 + (-3) \\ -7 + 5 \end{pmatrix} BC⃗=(1−2)\vec{BC} = \begin{pmatrix} 1 \\ -2 \end{pmatrix}

    The final answer is (1−2)\begin{pmatrix} 1 \\ -2 \end{pmatrix}.

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