I will assume you want me to demonstrate the integration process for Exercise 6 (1)a. This means I will find the function whose indefinite integral is given by the expression in (1)a, and then integrate that function to verify the result.
Given answer for Exercise 6 (1)a: F(x)=4x3+3x2β5x+c.
Step 1: Determine the function f(x) that was integrated to obtain F(x).
To do this, we find the derivative of F(x).
f(x)=dxdβ(4x3+3x2β5x+c)
f(x)=4β
3x3β1+3β
2x2β1β5β
1x1β1+0
f(x)=12x2+6xβ5
Step 2: Integrate f(x) to verify the given answer.
We need to find β«(12x2+6xβ5)dx.
Using the power rule for integration, β«xndx=n+1xn+1β+C:
β«(12x2+6xβ5)dx=β«12x2dx+β«6xdxββ«5dx
=12(2+1x2+1β)+6(1+1x1+1β)β5x+c
=12(3x3β)+6(2x2β)β5x+c
=4x3+3x2β5x+c
The result matches the given expression.
The verified indefinite integral is:
4x3+3x2β5x+cβ
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