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Given answer for Exercise 6 (1)a: F(x) = 4x³ + 3x² − 5x + c.

Mathematics

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Answer

4x3+3x2−5x+c\mathbf{4x^3 + 3x^2 - 5x + c}

Step-by-step solution

2 steps

I will assume you want me to demonstrate the integration process for (1)a. This means I will find the function whose indefinite integral is given by the expression in (1)a, and then integrate that function to verify the result.

Given answer for (1)a: F(x)=4x3+3x2−5x+cF(x) = 4x^3 + 3x^2 - 5x + c.

  1. Determine the function f(x)f(x) that was integrated to obtain F(x)F(x).

    To do this, we find the derivative of F(x)F(x).

    f(x)=ddx(4x3+3x2−5x+c)f(x) = \frac{d}{dx}(4x^3 + 3x^2 - 5x + c) f(x)=4⋅3x3−1+3⋅2x2−1−5⋅1x1−1+0f(x) = 4 \cdot 3x^{3-1} + 3 \cdot 2x^{2-1} - 5 \cdot 1x^{1-1} + 0 f(x)=12x2+6x−5f(x) = 12x^2 + 6x - 5
  2. Integrate f(x)f(x) to verify the given answer.

    We need to find ∫(12x2+6x−5) dx\int (12x^2 + 6x - 5)\,dx.
    Using the power rule for integration, ∫xn dx=xn+1n+1+C\int x^n\,dx = \frac{x^{n+1}}{n+1} + C:

    ∫(12x2+6x−5) dx=∫12x2 dx+∫6x dx−∫5 dx\int (12x^2 + 6x - 5)\,dx = \int 12x^2\,dx + \int 6x\,dx - \int 5\,dx =12(x2+12+1)+6(x1+11+1)−5x+c= 12 \left(\frac{x^{2+1}}{2+1}\right) + 6 \left(\frac{x^{1+1}}{1+1}\right) - 5x + c =12(x33)+6(x22)−5x+c= 12 \left(\frac{x^3}{3}\right) + 6 \left(\frac{x^2}{2}\right) - 5x + c =4x3+3x2−5x+c= 4x^3 + 3x^2 - 5x + c

    The result matches the given expression.

    The verified indefinite integral is:

    4x3+3x2−5x+c\mathbf{4x^3 + 3x^2 - 5x + c}
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