This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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b) i) Resistivity of a conductor is a fundamental property of the material that quantifies how strongly it resists the flow of electric current. It is defined as the resistance of a conductor of unit length and unit cross-sectional area. ii) Step 1: Convert the diameter to meters and calculate the radius. Given diameter d = 1.5 mm = 1.5 × 10^-3 m. The radius r is half of the diameter: r = (d)/(2) = 1.5 × 10^-3 m2 = 0.75 × 10^-3 m Step 2: Calculate the cross-sectional area A of the wire. The cross-sectional area of a circular wire is given by A = r^2. A = 3.14 × (0.75 × 10^-3 m)^2 A = 3.14 × (0.5625 × 10^-6 m^2) A = 1.76625 × 10^-6 m^2 Step 3: Calculate the resistance R using the formula R = (L)/(A). Given resistivity = 1.7 × 10^-8 m and length L = 20 m. R = (1.7 × 10^-8 m) × 20 m1.76625 × 10^-6 m^2 R = 34 × 10^-81.76625 × 10^-6 R = (34)/(1.76625) × 10^-2 R ≈ 19.249 × 10^-2 R ≈ 0.192 The resistance of the wire is 0.192 . Send me the next one 📸