Given f(x) = x2 − px + q. Since f(x) is divisible by (x+a), by the Factor Theorem, f(-a) = 0.

Step 1: Apply the Factor Theorem to $f(x)$.
Given $f(x) = x^2 - px + q$. Since $f(x)$ is divisible by $(x+a)$, by the Factor Theorem, $f(-a) = 0$.

$$f(-a) = (-a)^2 - p(-a) + q = 0$$ $$a^2 + pa + q = 0 \quad (1)$$

Step 2: Apply the Factor Theorem to $g(x)$.
Given $g(x) = x^2 + lx + m$. Since $g(x)$ is divisible by $(x+a)$, by the Factor Theorem, $g(-a) = 0$.

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