a)i) Calculate ∣l−k∣, correct to one decimal place.
Given k=(4−3) and l=(−57).
Step 1: Calculate the vector l−k.
l−k=(−57)−(4−3)=(−5−47−(−3))=(−910)
Step 2: Calculate the magnitude of l−k.
∣l−k∣=(−9)2+(10)2=81+100=181
Step 3: Round the magnitude to one decimal place.
181≈13.4536...∣l−k∣≈13.5
ii) Find the vector r such that k+r=2l.
Step 1: Rearrange the equation to solve for r.
r=2l−k
Step 2: Substitute the given vectors k and l.
r=2(−57)−(4−3)
Step 3: Perform the scalar multiplication and vector subtraction.
r=(2×−52×7)−(4−3)=(−1014)−(4−3)=(−10−414−(−3))=(−1417)
The vector r is (−1417).
b) Given that A(1,3), B(−2,−1) and C(2,3n) where n is a constant.
i) Find ∣AB∣ and ∣BA∣.
Step 1: Calculate the vector AB.
AB=B−A=(−2−1−1−3)=(−3−4)
Step 2: Calculate the magnitude ∣AB∣.
∣AB∣=(−3)2+(−4)2=9+16=25=5
So, ∣AB∣=5.
Step 3: Calculate the vector BA.
BA=A−B=(1−(−2)3−(−1))=(1+23+1)=(34)
Step 4: Calculate the magnitude ∣BA∣.
∣BA∣=(3)2+(4)2=9+16=25=5
So, ∣BA∣=5.
ii) Find the value of n if BC=(4−5).
Step 1: Express the vector BC using the coordinates of B and C.
B(−2,−1)C(2,3n)BC=C−B=(2−(−2)3n−(−1))=(2+23n+1)=(43n+1)
Step 2: Equate this expression for BC to the given vector (4−5).
(43n+1)=(4−5)
Step 3: Equate the y-components to solve for n.
3n+1=−53n=−5−13n=−6n=3−6n=−2
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Here's the solution to the vector problem. a) i) Calculate |l - k|, correct to one decimal place. Given k = 4 \\ -3 and l = -5 \\ 7 . Step 1: Calculate the vector l - k. l - k = -5 \\ 7 - 4 \\ -3 = -5 - 4 \\ 7 - (-3) = -9 \\ 10 Step 2: Calculate the magnitude of l - k. |l - k| = sqrt((-9)^2 + (10)^2) = sqrt(81 + 100) = sqrt(181) Step 3: Round the magnitude to one decimal place. sqrt(181) ≈ 13.4536... |l - k| ≈ 13.5 ii) Find the vector r such that k + r = 2l. Step 1: Rearrange the equation to solve for r. r = 2l - k Step 2: Substitute the given vectors k and l. r = 2 -5 \\ 7 - 4 \\ -3 Step 3: Perform the scalar multiplication and vector subtraction. r = 2 × -5 \\ 2 × 7 - 4 \\ -3 = -10 \\ 14 - 4 \\ -3 = -10 - 4 \\ 14 - (-3) = -14 \\ 17 The vector r is -14 \\ 17 . b) Given that A(1,3), B(-2,-1) and C(2,3n) where n is a constant. i) Find |AB| and |BA|. Step 1: Calculate the vector AB. AB = B - A = -2 - 1 \\ -1 - 3 = -3 \\ -4 Step 2: Calculate the magnitude |AB|. |AB| = sqrt((-3)^2 + (-4)^2) = sqrt(9 + 16) = sqrt(25) = 5 So, |AB| = 5. Step 3: Calculate the vector BA. BA = A - B = 1 - (-2) \\ 3 - (-1) = 1 + 2 \\ 3 + 1 = 3 \\ 4 Step 4: Calculate the magnitude |BA|. |BA| = sqrt((3)^2 + (4)^2) = sqrt(9 + 16) = sqrt(25) = 5 So, |BA| = 5. ii) Find the value of n if BC = 4 \\ -5 . Step 1: Express the vector BC using the coordinates of B and C. B(-2,-1) C(2,3n) BC = C - B = 2 - (-2) \\ 3n - (-1) = 2 + 2 \\ 3n + 1 = 4 \\ 3n + 1 Step 2: Equate this expression for BC to the given vector 4 \\ -5 . 4 \\ 3n + 1 = 4 \\ -5 Step 3: Equate the y-components to solve for n. 3n + 1 = -5 3n = -5 - 1 3n = -6 n = (-6)/(3) n = -2 That's 2 down. 3 left today — send the next one.