Step 1: Identify the given matrices.
The matrix P is given as:
P=(2−310)
The 2×2 unit matrix I is:
I=(1001)
Step 2: Calculate P2.
P2=P×P=(2−310)(2−310)
Perform matrix multiplication:
P2=((2)(2)+(1)(−3)(−3)(2)+(0)(−3)(2)(1)+(1)(0)(−3)(1)+(0)(0))
P2=(4−3−6+02+0−3+0)
P2=(1−62−3)
Step 3: Calculate 2P.
Multiply each element of matrix P by 2:
2P=2(2−310)=(2×22×(−3)2×12×0)
2P=(4−620)
Step 4: Calculate 4I.
Multiply each element of matrix I by 4:
4I=4(1001)=(4×14×04×04×1)
4I=(4004)
Step 5: Evaluate P2−2P+4I.
Substitute the calculated matrices into the expression:
P2−2P+4I=(1−62−3)−(4−620)+(4004)
First, perform the subtraction:
(1−62−3)−(4−620)=(1−4−6−(−6)2−2−3−0)
=(−300−3)
Now, perform the addition:
(−300−3)+(4004)=(−3+40+00+0−3+4)
=(1001)
The result is the 2×2 unit matrix. Comparing this to the given options, it matches option C.
The final answer is (1001).
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