Given O is the center of the circle. KM is a diameter.

Here are the solutions for , determining the value of the lowercase letters and providing reasons.

Figure 1:
Given $O$ is the center of the circle. $KM$ is a diameter.

Step 1: Find $\angle JON$.
In $\triangle OJN$, $OJ = ON$ (radii). Therefore, $\triangle OJN$ is an isosceles triangle.

$$\angle ONJ = \angle OJN = 32^\circ$$

The sum of angles in $\triangle OJN$ is $180^\circ$.

$$\angle JON = 180^\circ - (\angle OJN + \angle ONJ)$$ $$$$