Here are the solutions for , determining the value of the lowercase letters and providing reasons.
Figure 1:
Given O is the center of the circle. KM is a diameter.
Step 1: Find ∠JON.
In △OJN, OJ=ON (radii). Therefore, △OJN is an isosceles triangle.
∠ONJ=∠OJN=32∘
The sum of angles in △OJN is 180∘.
∠JON=180∘−(∠OJN+∠ONJ)