Given OAC = 18^, so OCA = 18^.
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Problem 3.1:
Step 1: Find $y$.
$OA$ and $OC$ are radii, so $\triangle OAC$ is an isosceles triangle.
Given $\angle OAC = 18^\circ$, so $\angle OCA = 18^\circ$.
The sum of angles in $\triangle OAC$ is $180^\circ$.
$$y + 18^\circ + 18^\circ = 180^\circ$$
$$y + 36^\circ = 180^\circ$$
$$y = 180^\circ -
