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Create a quadratic polynomial whose sum and product of zeros are 1/4 and -1 respectively.

Mathematics

ScanSolve AI Answer

Answer

4x2−x−14x^{2} - x - 1

Step-by-step solution

5 steps
  1. Recall the sum and product of zeros for the quadratic ax2+bx+c=0ax^2 + bx + c = 0.

    Sum of zeros: s=−bas = -\frac{b}{a}

    Product of zeros: p=cap = \frac{c}{a}

    Given: s=14s = \frac{1}{4}, p=−14p = -\frac{1}{4}

    s=−ba=14s = -\frac{b}{a} = \frac{1}{4} p=ca=−14p = \frac{c}{a} = -\frac{1}{4}
  2. Choose a=4a = 4 to obtain integer coefficients.

    Substitute a=4a = 4 into sum formula:

    −b4=14-\frac{b}{4} = \frac{1}{4}

    Multiply both sides by -4:

    b=−1b = -1
  3. Substitute a=4a = 4 into product formula

    c4=−14\frac{c}{4} = -\frac{1}{4}

    Multiply both sides by 4:

    c=−1c = -1
  4. Form the quadratic polynomial.

    4x2+(−1)x+(−1)=4x2−x−14x^2 + (-1)x + (-1) = 4x^2 - x - 1
  5. Verify sum and product.

    Sum: −ba=−−14=14-\frac{b}{a} = -\frac{-1}{4} = \frac{1}{4}

    Product: ca=−14=−14\frac{c}{a} = \frac{-1}{4} = -\frac{1}{4}

    4x^{2} - x - 1

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