Given that x and y are positive whole numbers such that 2x+5y is divisible by 16, what are the possible values for x and y?

April 22, 2026Mathematics

ScanSolve AI Answer

April 22, 2026

Answer

$16k \ge 7$ , which implies $k \ge \frac{7}{16}$

Step 1: Understand the conditions. We are given that $x$ and $y$ are positive whole numbers, which means $x \ge 1$ and $y \ge 1$ . We are also given that $2x+5y$ is divisible by $16$ . This can be written as: $2x+5y = 16k$ where $k$ is a positive integer. Since $x \ge 1$ and $y \ge 1$ , the smallest possible value for $2x+5y$ is $2(1)+5(1) = 7$ . Therefore, $16k \ge 7$ , which implies $k \ge \frac{7}{16}$ . Since $k$

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Quick Answer

Understand the conditions. We are given that x and y are positive whole numbers, which means x 1 and y 1.

Asked on April 22, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 22, 2026

Step 1: Understand the conditions. We are given that x and y are positive whole numbers, which means x 1 and y 1. We are also given that 2x+5y is divisible by 16. This can be written as: 2x+5y = 16k where k is a positive integer. Since x 1 and y 1, the smallest possible value for 2x+5y is 2(1)+5(1) = 7. Therefore, 16k 7, which implies k (7)/(16). Since k