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Given the coordinates of 9 points, calculate the uncorrected coordinates.

Mathematics

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Step-by-step solution

4 steps

To calculate the uncorrelated coordinates (Δ\DeltaN and Δ\DeltaE), we find the difference in Northing and Easting between consecutive stations.

The formulas are:

ΔN=Nnext−Ncurrent\Delta N = N_{\text{next}} - N_{\text{current}} ΔE=Enext−Ecurrent\Delta E = E_{\text{next}} - E_{\text{current}}
  1. Calculate Δ\DeltaN and Δ\DeltaE for segment A to B.

    Given:
    NA=31276.100N_A = 31276.100, EA=51829.700E_A = 51829.700
    NB=31589.500N_B = 31589.500, EB=51900.300E_B = 51900.300

    ΔNAB=31589.500−31276.100=313.400\Delta N_{AB} = 31589.500 - 31276.100 = 313.400 ΔEAB=51900.300−51829.700=70.600\Delta E_{AB} = 51900.300 - 51829.700 = 70.600
  2. Calculate Δ\DeltaN and Δ\DeltaE for segment B to C.

    Given:
    NB=31589.500N_B = 31589.500, EB=51900.300E_B = 51900.300
    NC=31519.200N_C = 31519.200, EC=53096.700E_C = 53096.700

    ΔNBC=31519.200−31589.500=−70.300\Delta N_{BC} = 31519.200 - 31589.500 = -70.300 ΔEBC=53096.700−51900.300=1196.400\Delta E_{BC} = 53096.700 - 51900.300 = 1196.400
  3. Calculate Δ\DeltaN and Δ\DeltaE for segment C to D.

    Given:
    NC=31519.200N_C = 31519.200, EC=53096.700E_C = 53096.700
    ND=31226.900N_D = 31226.900, ED=52037.400E_D = 52037.400

    ΔNCD=31226.900−31519.200=−292.300\Delta N_{CD} = 31226.900 - 31519.200 = -292.300 ΔECD=52037.400−53096.700=−1059.300\Delta E_{CD} = 52037.400 - 53096.700 = -1059.300
  4. Complete the table with the calculated uncorrelated coordinates.

    The Δ\DeltaN and Δ\DeltaE values for each row correspond to the segment starting from that station.

    stationNorthingEastingΔNΔEbearingA31276.10051829.700313.40070.600B31589.50051900.300−70.3001196.400C31519.20053096.700−292.300−1059.300D31226.90052037.400\begin{array}{|c|c|c|c|c|c|} \hline \text{station} & \text{Northing} & \text{Easting} & \Delta N & \Delta E & \text{bearing} \\ \hline \text{A} & 31276.100 & 51829.700 & 313.400 & 70.600 & \\ \text{B} & 31589.500 & 51900.300 & -70.300 & 1196.400 & \\ \text{C} & 31519.200 & 53096.700 & -292.300 & -1059.300 & \\ \text{D} & 31226.900 & 52037.400 & & & \\ \hline \end{array}

    The completed table is:

    stationNorthingEastingΔNΔEbearingA31276.10051829.700313.40070.600B31589.50051900.300−70.3001196.400C31519.20053096.700−292.300−1059.300D31226.90052037.400\boxed{ \begin{array}{|c|c|c|c|c|c|} \hline \text{station} & \text{Northing} & \text{Easting} & \Delta N & \Delta E & \text{bearing} \\ \hline \text{A} & 31276.100 & 51829.700 & \mathbf{313.400} & \mathbf{70.600} & \\ \text{B} & 31589.500 & 51900.300 & \mathbf{-70.300} & \mathbf{1196.400} & \\ \text{C} & 31519.200 & 53096.700 & \mathbf{-292.300} & \mathbf{-1059.300} & \\ \text{D} & 31226.900 & 52037.400 & & & \\ \hline \end{array} }
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