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Given the definite integral:

April 3, 2026Mathematics

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10. (b) Find the value of $m$

Given the definite integral:

\int_{-2}^{m} (4x^2 - 2x + 9)\,dx = \frac{172}{3}

where $m$ is an integer.

Integrate the function $4x^2 - 2x + 9$ .
$\int (4x^2 - 2x + 9)\,dx = \frac{4x^3}{3} - \frac{2x^2}{2} + 9x = \frac{4x^3}{3} - x^2 + 9x$
Evaluate

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