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To evaluate the integral:

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Question 36:
The question asks to evaluate the integral:

∫قتا(س+ب)ظتا(س+ب) ds\int \text{قتا}(س+ب) \text{ظتا}(س+ب) \,ds
  1. Recall the standard integral for قتا(x)ظتا(x)\text{قتا}(x)\text{ظتا}(x).

    We know that the derivative of قتا(x)\text{قتا}(x) is −قتا(x)ظتا(x)-\text{قتا}(x)\text{ظتا}(x).
    Therefore, the integral of قتا(x)ظتا(x)\text{قتا}(x)\text{ظتا}(x) is −قتا(x)+C-\text{قتا}(x) + C.

  2. Apply this to the given integral.

    In this case, the argument is $(

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